Does anyone know how much reverse throw is applied to the cue ball when throw is applied to the object ball?
Does anyone know how much reverse throw is applied to the cue ball when throw is applied to the object ball?
Wouldn't that apply to the shot at hand?
Does anyone know how much reverse throw is applied to the cue ball when throw is applied to the object ball?
If the CB has very little inside english spin before contact, I can see how throw can reverse the spin of the CB post contact.But for most shots I don't think it will not reverse the spin...
Actually, the opposite is true on outside english shots provided the amount of OE spin on the CB is insufficient for perfect "gearing" english (the resulting shot will have positive throw). In this case, the CB will have more OE spin than it started out with....more than likely it will just reduce the amount of spin left on the CB.
Jsp, for what it's worth, I agree with both of your observations.If the CB has very little inside english spin before contact, I can see how throw can reverse the spin of the CB post contact.
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Actually, the opposite is true on outside english shots provided the amount of OE spin on the CB is insufficient for perfect "gearing" english (the resulting shot will have positive throw). In this case, the CB will have more OE spin than it started out with.
Exactly the same amount, but in the opposite direction along the tangent line.RicNic said:Does anyone know how much reverse throw is applied to the cue ball when throw is applied to the object ball?
If the CB has very little inside english spin before contact, I can see how throw can reverse the spin of the CB post contact.
Actually, the opposite is true on outside english shots provided the amount of OE spin on the CB is insufficient for perfect "gearing" english (the resulting shot will have positive throw). In this case, the CB will have more OE spin than it started out with.
Does anyone know how much reverse throw is applied to the cue ball when throw is applied to the object ball?
Does anyone know how much reverse throw is applied to the cue ball when throw is applied to the object ball?
I like the question. In fact, I love the question. The examination and answer should open up a lot of eyes for both stop/stun shots and cut shots.
Freddie <~~~ yeah, no wonder I scratched
Another way to put it is that the object ball is thrown by the slightly sticky surface of the cue ball pulling it to the side. Since the cue ball is not attached to the table, it will have be pushed in the other direction. Depending on the situation, the cue ball will be going faster or slower along the tangent line right after the contact due to that frictional force against the object ball.Jsp, for what it's worth, I agree with both of your observations.
Exactly the same amount, but in the opposite direction along the tangent line.
For instance, the cueball has a certain component of velocity in the direction of the tangent line, call it Vct. If the object ball is thrown in the same direction with velocty Vot, then the cueball's new velocity along the tangent will be Vct - Vot. If the object ball is thrown in the opposite direction along the tangent line because of excessive outside english, then the cueball's new velocity will be Vct + Vot.
This is just Newton's Third Law of action/reaction.
Jim
Can you go ahead and answer it?
Well, in some sense there is less effect on the cue ball's motion than on the object ball. Suppose the cue ball lands full on the object ball at a speed of 10 inches per second and with enough spin to give the object ball a speed to the side of 1/2 inch per second (a "slope" of 20:1, or about 3 degrees of throw). Suppose the cue ball has no draw or follow. The cue ball will be moving to the other side at 1/2 inch per second. If the rolling friction on the cloth is such that the cue ball rolls one inch to the side before stopping, the object ball will roll about 400 times as far in total (assuming it doesn't hit a cushion) for a total distance of 400 inches roughly. With a slope of 20:1 off dead straight ahead, that means it will go to the side 20 inches in its 400 inches of travel. If you count "total distance to the side" as the important parameter, there was more effect on the OB than the CB.Thanks to all for considering this question. As a number of you have suggested, there is an equal and opposite reaction on the cue ball, the magnitude and direction, of which, depend upon the specific conditions, i.e., stun, draw, etc. Published papers on this concept appear to be in need of correction if they say that there is none or very little effect on the cue ball's motion. We would all benefit if someone would explore this effect in some mathematical way, and applied in a practical way.