Point length after turning to final size?

xianmacx

xianmacx

AzB Silver Member
Silver Member
Hello Cuemakers,

I am having a cue made from an oversized full splice blank. At the top of the points it is currently .12 oversized from final dimensions. Once the blanks is turned down, that .12, how much would you ball park the points will shorten? I assume it depends on the angle the splice was done, but as a estimate what would you think?

Thanks,
Ian
 
xianmacx said:
Hello Cuemakers,

I am having a cue made from an oversized full splice blank. At the top of the points it is currently .12 oversized from final dimensions. Once the blanks is turned down, that .12, how much would you ball park the points will shorten? I assume it depends on the angle the splice was done, but as a estimate what would you think?

Thanks,
Ian
Click to expand...
on my bflys, .100" equals approx. 1 inch
 
ian, it should be less than that in your case
because your points are cut at a steeper angle than my bflys
 
DoubleD said:
This is easy to figure out.

Measure the length of the point now. Call this 'a'.

Measure the width of the base. Logically, we will call this 'b'.

You have enough data to figure out the depth of the vee at the base (we'll call this 'd').

d=b/1.414

Now envision a section view of the cue through the center of the point, you have a triangle formed by the point.

Regardless of how you taper this now, if you know that you are taking 'x' off the thickness of the cue (diameter based) at the tip of the points, your point length, "a" will change to "a' " by the formula:

a'=a*((d-(x/2))/d)

Math is fun!

dld
Click to expand...

Gotta love math, so just to be clear, is this image correct for a and b?

spliced_butt_no_veneeredit_zpsf0073880.jpg
 
Ok so with my math, the points are 7.25 now and will go down to 6.56 once turned.

My last question, I assume I should measure B around the curvature of the blank and not linear with calipers?

Ian
 
DoubleD said:
This is easy to figure out.

Measure the length of the point now. Call this 'a'.

Measure the width of the base. Logically, we will call this 'b'.

You have enough data to figure out the depth of the vee at the base (we'll call this 'd').

d=b/1.414

Now envision a section view of the cue through the center of the point, you have a triangle formed by the point.

Regardless of how you taper this now, if you know that you are taking 'x' off the thickness of the cue (diameter based) at the tip of the points, your point length, "a" will change to "a' " by the formula:

a'=a*((d-(x/2))/d)

Math is fun!

dld
Click to expand...

This is the slam dunk answer of the year.

-roger <----- not all asians are good at math.
 
DoubleD said:
This is easy to figure out.

Measure the length of the point now. Call this 'a'.

Measure the width of the base. Logically, we will call this 'b'.

You have enough data to figure out the depth of the vee at the base (we'll call this 'd').

d=b/1.414 ...
Click to expand...

If it's a 90-degree vee, isn't d = b/2?
 
DoubleD said:
No.

Pythagorean theorem: A^2 + B^2 = C^2

Since C is the measured length (b in my example) and the triangle is isosceles (A=B):

C= sqrt(2A^2)

C=sqrt (2) * A

The square root of 2=1.414, thus C=1.414 * A

dld
Click to expand...

b/1.414 would be the length of one of the legs of the original isosceles triangle. But that's not the depth perpendicular to the surface. To determine the depth of the vee, wouldn't you drop a perpendicular from the center of b to the vee, i.e., to the intersection of the other two legs? The length of that perpendicular is b/2.
 
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