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Tennesseejoe
03-13-2010, 11:12 AM
With all the controversy about pattern racking, this may solve some of the problem. Rack 10 ball and after the break remove the lowest numbered ball on the table. Then continue to play.


Any opinions?

Vahmurka
03-13-2010, 11:39 AM
why remove lowest numbered? Remove the 10 then, 9 being in the middle of the rack. But it won't be 9-Ball if you rack 10 balls, because the break and its outcome differs.

Beware_of_Dawg
03-13-2010, 01:05 PM
why not rack all 15 balls like you would for 8ball and remove the highest 6 balls? lol.

sounds like mental mastrabation, just play 10 ball or accept the short comings of 9 ball and play that.

No offense of course, just saying.

Andrew Mathias
03-13-2010, 01:12 PM
I say just play ten ball

poolplayer2093
03-13-2010, 01:21 PM
With all the controversy about pattern racking, this may solve some of the problem. Rack 10 ball and after the break remove the lowest numbered ball on the table. Then continue to play.


Any opinions?

Why not just play 10 ball if you've already got it racked

Blackball75
03-13-2010, 01:32 PM
10-ball > 9-ball

Celtic
03-13-2010, 01:35 PM
With all the controversy about pattern racking, this may solve some of the problem. Rack 10 ball and after the break remove the lowest numbered ball on the table. Then continue to play.


Any opinions?

Why? I mean that seriously? Why the heck would you even dream up such an absurd, confusing, and goofy way of doing things? Why not just break 10-ball and then play.... 10-BALL!

Cripe,

"ok guys, how about we rack 8-ball, now after the break we have the players take a deck of cards that are marked up with the number of the balls 1-15, the player who did not break picks a card, the ball on the card can be removed but only if the breaker is not wearing a shirt the color of that ball, in which case the breaker is allowed to pick 2 cards and remove both of those balls, but only if those 2 balls cannot be added together to a multiple of the age of the other player....."


FFS people, KISS!!!! Play 10-ball, it is bloody simple and it works.

Fobstarr
03-13-2010, 11:39 PM
"ok guys, how about we rack 8-ball, now after the break we have the players take a deck of cards that are marked up with the number of the balls 1-15, the player who did not break picks a card, the ball on the card can be removed but only if the breaker is not wearing a shirt the color of that ball, in which case the breaker is allowed to pick 2 cards and remove both of those balls, but only if those 2 balls cannot be added together to a multiple of the age of the other player....."

read the first 10 words and gave up :thumbup: