5C Spin Indexer

Busbee Cue

AzB Silver Member
Silver Member
Hello,

Is it possible to index 16 equal holes with this type of indexer?
I know I need 22.5 spaces between each hole but I am baffled
on how to go about it.

Any input would be appreciated.
 

KJ Cues

Pro Cue Builder & Repair
Silver Member
Randy,

There is no 1/2 degree on the fixture so you have to be creative.
If you were to do 1/2 the slots, they would be done on 45*, correct ?
Do them.
Now, remove the billet from the fixture. Find and scribe center btwn two slots.
Re-install the billet using your scribed mark as zero.
Do another 8, 45* slots and you're done. Re-setting your billet accurately is key.

We've had this discussion previously. Royce had an alternative method that works also.
Do 1/2 the slots @ 22*, do the other 1/2 @ 23*.
1* offset on a circumference of .840" is next to impossible to visually detect.
 

Busbee Cue

AzB Silver Member
Silver Member
Randy,

There is no 1/2 degree on the fixture so you have to be creative.
If you were to do 1/2 the slots, they would be done on 45*, correct ?
Do them.
Now, remove the billet from the fixture. Find and scribe center btwn two slots.
Re-install the billet using your scribed mark as zero.
Do another 8, 45* slots and you're done. Re-setting your billet accurately is key.

We've had this discussion previously. Royce had an alternative method that works also.
Do 1/2 the slots @ 22*, do the other 1/2 @ 23*.
1* offset on a circumference of .840" is next to impossible to visually detect.

Thanks KJ,

The answer was so simple that I did not think of doing it that way.
 

MVPCues

AzB Silver Member
Silver Member
It also isn't a necessity to have the pin in the hole for the .5 positions. Index 0 normally, cut. Index 22 with the pin inside. Pull pin, index to 23, insert pin. By doing this you get the feel for how far the travel is for 1 degree. Pull pin. Spin wheel backwards 1/2 degree travel. If the pin does not slide in either 22 or 23 hole (test gently), tighten and cut.

A 22.3-22.4 or a 22.6-22.7 position due to error in estimating the 1/2 degree travel would never be detected.
 
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