Here is a video of me shooting "center ball" at a medium speed but it can be done at any speed. At any speed, it is a stop shot + about 6". My teacher states this is the second most important shot in pool. I'm shooting this on a straight in shot so it can be demonstrated but the value is the angle the cue ball goes off the object ball. We all know the stop shot goes off on tangent and how the rolling ball shot goes off, but there is a special angle in between these two tracks that the "center ball" will track on. He uses this track for shape. There are many spots on the table where it's impossible to get there without this shot.
If you put a OB on the one ball spot and hit a stop shot at an angle, the cue ball will scratch. The "center ball" will hit the end rail about 6" on the end rail from the pocket. Here is the way you'll know you've got it. Put a ball one ball width up from the one ball spot. Now the "center ball" shot will scratch. https://youtu.be/fjEGe0_rP2k
"At any speed, it is a stop shot + about 6".
This statement is not true. At a softer speed the cb begins rolling before it hits the ob, which causes it to continue rolling forward after striking the ob. As firm as you hit the first shot, and as close as the cb was to the ob, a center hit would've created a stop shot -- the cb slides into the ob and stops dead. Your +6" was due to hitting slightly above center cb whether you realized it or not. Either that ir your cb is a touch heavier than the ob. Physics is physics, no way around it.:smile: