Gambling Lingo Question
- Thread starter NewStroke
- Start date
Dan,
It means that someone must make 16 balls in his pocket before the other guy gets to 8 balls in One Pocket.
I believe that as balls are made they are spotted until you get to a point where 15 total balls are needed by both opponents.
I don't play One Pocket but this his what I believe happens.
It means that someone must make 16 balls in his pocket before the other guy gets to 8 balls in One Pocket.
I believe that as balls are made they are spotted until you get to a point where 15 total balls are needed by both opponents.
I don't play One Pocket but this his what I believe happens.
You mean 16 balls not 15 balls. A Normal game is 8-8 right. If you gave me 9-7 no one has to spot a ball but if you gave me 9-8 you would have to spot 1 ball.
jambalaya!!
and a crawfish pie.....
thanks...my brain must have fried in the sun today lol...post edited
And filet gumbo.
"Long count" handicaps in One Pocket
That is correct. And, the important thing to remember about the spot is that the spotting doesn't take place until *after* the player needing sixteen has pocketed his first 8 balls. Then, all 8 of those balls he just pocketed spot-up simultaneously, in a line, from the foot spot down to the cushion. This prevents the situation whereby the player sets up for an easy spot-shot (by cue ball control) after pocketing his 8th ball, spot up one ball, pocket that ball, control whitey to set up for another easy spot-shot (e.g. draw back a bit), spot-up another ball, pocket it, control whitey for another easy spot-shot (e.g. draw back a bit), spot up another ball, ...ad infinitum until all 8 balls that he/she previously pocketed, are pocketed again.
Simultaneous spotting of all 8 balls prevents that "gimme" situation. Here's a good table illustrating how to handle these "Long Count" situations:
http://onepocket.org/handicaps.htm
-Sean
That is correct. And, the important thing to remember about the spot is that the spotting doesn't take place until *after* the player needing sixteen has pocketed his first 8 balls. Then, all 8 of those balls he just pocketed spot-up simultaneously, in a line, from the foot spot down to the cushion. This prevents the situation whereby the player sets up for an easy spot-shot (by cue ball control) after pocketing his 8th ball, spot up one ball, pocket that ball, control whitey to set up for another easy spot-shot (e.g. draw back a bit), spot-up another ball, pocket it, control whitey for another easy spot-shot (e.g. draw back a bit), spot up another ball, ...ad infinitum until all 8 balls that he/she previously pocketed, are pocketed again.
Simultaneous spotting of all 8 balls prevents that "gimme" situation. Here's a good table illustrating how to handle these "Long Count" situations:
http://onepocket.org/handicaps.htm
-Sean
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I think the way it's supposed to be done, The owed balls are spotted at the end of an inning. If I owe 8 balls at the start of my inning and run 5 and then miss, Those 5 balls are spotted and I start my next inning with 3 balls still being owed. The only time the balls would come up before the end of an inning would be if I ran all the balls remaining on the table but still didn't make enough balls to make up a winning score. My owed balls would then be spotted and I would continue to shoot.
sliprock:
You are exactly correct! I tried my best to cover all details, but I missed this one. And it's an important one, too!
I don't play Long Count spots much at all; the folks I play One Pocket with are generally either the same speed as I, or perhaps a bit less or bit more. It's usually even-up, but if we *do* play with a handicap, it's always a Natural Count handicap.
Thanks for the clarification!
-Sean
This long count spotting is a bit confusing.
Please tell me if I have this correct:
The player with the long count handicap will spot his owed balls after every inning he makes balls UNTIL he owes no more. Ie. He brings the total # down to the natural count - the "natural count" being that which totals 16. So if the game handicap was set at 20-5, the long counter spots his potted balls until he's down to 11 more needed for the W.
Secondly, in event the long count player runs all balls off the table and still needs more, he spots all the balls he needs to win the game and proceeds with his inning.
Please tell me if I have this correct:
The player with the long count handicap will spot his owed balls after every inning he makes balls UNTIL he owes no more. Ie. He brings the total # down to the natural count - the "natural count" being that which totals 16. So if the game handicap was set at 20-5, the long counter spots his potted balls until he's down to 11 more needed for the W.
Secondly, in event the long count player runs all balls off the table and still needs more, he spots all the balls he needs to win the game and proceeds with his inning.