Are we ignoring gravity, which will make the ball drop once it get off the table at 1/2 g t^2? If we don't ignore gravity, then then when the ball clears the other end of the table, it will fall due to gravity. At 32 ft/s^2, the ball will hit the ground in about 0.4seconds. If the ball leaves the table at, say , 30 mph horizontally (the cueball slows down before ever getting to the end of the table), then that means the cueball travels about 17 ft or se before it hits the ground, ignoring air drag. If we don't ignore air drag, then you have to add the air drag force on a nice, non-stitched cueball, which decreases the 17'.
Now, if you're ignoring gravity and drag coefficient, then you're into a Physics 101 exam, which doesn't ever represent reality. If you don't ignore gravity, but want to know how far the cueball will roll, then you have to define the material and topography of whatever the cueball is rolling on.
Edit: I missed that you made this more goofy with an unlimited length of table. Then it’s just the initial velocity and the table resistance.
I can't believe I entertained you on this, but I'm on a boring call.
Freddie <~~~ someone check my math