One Pocket Rule clarification?

jtompilot

AzB Silver Member
Silver Member
I've had good players give me 8/5 or 9/5. How is that a prop bet? With that type of spot you could certainly shoot the game winning ball for both players. So in that case the shooter wins.
 

Lesh

One Hole Thinkifier
Silver Member
Shooter wins.

Doesn't matter if the shooting player makes 14 balls in the opponent pocket and 1 that drops dead last in his own pocket . Shooter wins. He is shooting... hence, the name Shooter. You see, the shooter shot the shot and reached their number while they were shooting their inning and could legally still continue shooting even if they hadn't made their number.... cuz, you know, they shot a legal shot as the shooter.

Thanks,

Lesh

PS: Shooter
 

vagabond

AzB Silver Member
Silver Member
This issue was discussed many years ago and late Grady Mathews provided clarification/his point of view on this issue.

Before the One pocket.Org published the rules, it solicited the opinions/input of the posters on it`s web site.

Any argument will be settled in favor of the guy that is willing to use the gun and go to prison but not in favor of a big guy. In USA the size of the body does not matter and a gram of lead matters.
 

Poolshootindon

Registered Pool Offender
Silver Member
"3.2 In the event that a player pockets both their own game winning ball, and their opponent’s game winning ball, both on the same legal stroke, then the shooting player wins. There are no ‘ties’, and it does not matter which ball drops first, as long as they both drop as a result of the same stroke."

Since it is impossible for 3.2 to come up in any tournament where there is no spot, it would be wise for players to agree before a match to follow this rule if there is a spot.
 

Runner

AzB Silver Member
Silver Member
Shooter.

It doesn't matter if you sink one for your opponent if you made your winning ball... YOU'RE at the table. Shooter wins.
 
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