Search results

One them is the kid who made it to the semis in the World 10-ball Championship.

I'll take your bet on that. FIFA rules in effect . . .:rolleyes:

Hustling and taking on a locked game are just as prevalent in the Philippines like anywhere in the US. It's actually even worse. Which is also the most striking fact about Filipino players, they are all gamblers. They have honed the gambling mentality which even the most experienced players in...

This very much a standard practice most specially in book collecting business when widower will just try to unload anything they don't want.

Oh hush people, some people have to earn a living. I'm still waiting for Kevin Trudeau to come out with a pill to make me look like George Clooney. :D

I suggest eating bean burrito for extra "punch" during the match. :D

Doesn't your (sighting and aiming) lines also follow the same proportion because of your perception making the balls theoretically the same size? Just a thought . . .

looks like for 5'9"+ peeps it's doable up too a little over halfway the table.

Ronnie Alcano putting the bridge over his shoulder for a better stroke. Looks funny but it makes sense. http://jp.youtube.com/watch?v=iHffyitzQfA&feature=related

You must put this in context. Read the first post. Some people are assuming that spacing out the Philippine contigent is in effect helping them out because they don't knock each other out in the early rounds. It's not a team competition, but the poster didn't say why Lee Van Corteza wasn't...

This is done to avoid one bracket to be loaded with players from one country. When a bracket(there are 4 starting brackets in US Open) is loaded with players from one country it's very likely that they will dominate that bracket. This is specially true for players from the Philippines who are...

Dr. Dave, I think he is asking if you can express this equation F = G * m1 * m2 / d^2 to something like this; F = G * m1 * m2 / d^2 = m1g1(moon's force experience at any point equal to the distance of Earth and moon) + m2g2(Earth's force experience at any point equal to the distance of Earth...

The acceleration due to gravity is what changing since your mass remains constant.

Your mechanical system is actually the description you gave; "the assumption of course is that the acceleration doesn't stay positive indefinitely, but eventually reaches zero at some time." It's not all "real" mechanical systems. Unless otherwise you assume all "real" mechanical systems behaves...

Good job. A+

Ah, how is that attractive force normally referred to and what does it imply? The system YOU and EARTH, has a net zero acceleration. But when you isolate the body YOU and treat it as a separate system, YOU is accelerating by 9.8m/s^2. I was just hoping for people to use terms and the associated...

F=ma; your mass is contant, what does change to have a lesser weight on the moon? Interestingly enough as long as there is a push or pull there is acceleration. No argument on that. Sorry, I'm just being testy about achieving the most powerful contact which is to not ever let go of...

And did I mention the most power? :D

PJ, remember the third law of motion, opposite and equal reaction. You always have an acceleration component even when standing still. It's just that the forces are cancelling out which shouldn't be confused with acceleration cancelling out. That's why you will weigh less on the surface of the moon.

This one does not apply to all mechanical system: "Also by the definition of acceleration, peak velocity is achieved exactly when the acceleration is zero." What you are suggesting mostly concerns classical pendulum mechanical system in which the acceleration acts vertically and the...