watch the 10 ball at snookers this weekend congrads to mike on the win big head plays lights out. what i am talking about is most of the last players in the tournament when they broke the balls the 10 ball never moved unless it was kicked by another ball.my question is does that mean the 10 ball was not frozen when racked?
10 ball break
- Thread starter dbrown
- Start date
The better (more frozen) the rack, the less the 10-ball moves.
Think of it as "transfer of energy." The 10-ball is the only ball in the rack that is surrounded by other balls on all sides -- every other ball has an "out", an escape route from the rack. But the 10-ball is hemmed in on all sides. Any energy it gets from the balls in the first and second rows is immediately transfered to the balls behind it and to its sides. Those are the balls that move because there's nothing in their way to stop them.
And the two corner balls travel the furthest even though they're farthest from the point of impact (the CB hitting the one-ball). It's because they have no balls behind them and no balls to the outside -- so they don't give up any energy.
Think of it as "transfer of energy." The 10-ball is the only ball in the rack that is surrounded by other balls on all sides -- every other ball has an "out", an escape route from the rack. But the 10-ball is hemmed in on all sides. Any energy it gets from the balls in the first and second rows is immediately transfered to the balls behind it and to its sides. Those are the balls that move because there's nothing in their way to stop them.
And the two corner balls travel the furthest even though they're farthest from the point of impact (the CB hitting the one-ball). It's because they have no balls behind them and no balls to the outside -- so they don't give up any energy.