correct math
Same formula I was taught for double elimination:thumbup:
With a standard double-elimination format, the total number of matches for a tournament with N players is 2N-2.
If the final match is true double elimination and it goes to a second set, and you want to count that second set as another match, then the total is 2N-1.
So, the total number of matches would be as follows (add one to each if the finals goes two sets):
4 players = 6 matches
8 players = 14 matches
16 players = 30 matches
32 players = 62 matches
64 players = 126 matches
128 players = 254 matches
256 players = 510 matches
Same formula I was taught for double elimination:thumbup: