danielrogers1
Registered
This question came up last night during league, and I'm looking to see if anyone has a reference for an official rule, or get general consensus.
BCA pool league, using 10 point scoring (winner of rack gets 10 points, loser gets 1 point for each ball of their group pocketed)
Table is open after the break, and while attempting to legally pocket a ball and declare their group they pocket the 8-ball.
How would this be scored, if there are ball(s) from both groups pocketed? Would it automatically be a 10-0 since it was an open table and the losing player hadn't "scored" any points for legally pocketing a ball? Or would the winning player receive the group with the most balls pocketed, while the losing player would receive the group with the lesser balls pocketed?
For example if 2 solids and 1 stripe have been pocketed, but the table is still open, and the 8 is made early, winning player receives solids and 10 points, and losing player receives stripes and scores 1 point? Or automatic 10-0?
BCA pool league, using 10 point scoring (winner of rack gets 10 points, loser gets 1 point for each ball of their group pocketed)
Table is open after the break, and while attempting to legally pocket a ball and declare their group they pocket the 8-ball.
How would this be scored, if there are ball(s) from both groups pocketed? Would it automatically be a 10-0 since it was an open table and the losing player hadn't "scored" any points for legally pocketing a ball? Or would the winning player receive the group with the most balls pocketed, while the losing player would receive the group with the lesser balls pocketed?
For example if 2 solids and 1 stripe have been pocketed, but the table is still open, and the 8 is made early, winning player receives solids and 10 points, and losing player receives stripes and scores 1 point? Or automatic 10-0?