8 ball break

Philthepockets

AzB Silver Member
Silver Member
Is this ruling correct?

If you break in 8‑ball and all seven balls of one group (all solids or all stripes) drop on the break, the ruling is actually very simple — and it’s the same across all major rule sets.


🎱

Pocketing balls on the break does not give you ball‑in‑hand or any special continuation. The break is always considered its own turn. Once the balls stop moving, your inning ends unless you pocketed the 8‑ball (which is a separate rule).

So even if you made all seven solids (or all seven stripes):

  • You do not continue shooting
  • Your opponent comes to the table
  • Your opponent is automatically assigned the other group
  • Your opponent must shoot at the remaining seven balls of their group
 
If a ball is made, you continue shooting!
I don’t know what is the ruling if all balls of a group are made on the break, whether you shoot the 8 or the other group, my guess is that we will never know as this probably can’t happen with normal legal rack

My guess it that since it is an open table, you can shoot the 8 for the win
 
What rule set is that?

I've never heard of an 8-ball rule set where the player who breaks does not continue to shoot if he made at least one ball on the break.

The only difference lies in whether the table remains open after balls of a single suit are made on the break or if he is automatically assigned the suit he made...
 
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