http://endeavor.med.nyu.edu/~wei/pool/9egg/
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Good luck, my friends.
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Good luck, my friends.
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90 degree cut
- Thread starter Skeezicks
- Start date
At least this is a more descriptive subject than an aiming heading.
Many good players can't describe what they are doing, just that it works. I think an actual 90 deg cut is not possable but sure wouldn't bet a paticular set up couldn't be made. One possability is the cb is actually bouncing and comes down on the ob.
Many good players can't describe what they are doing, just that it works. I think an actual 90 deg cut is not possable but sure wouldn't bet a paticular set up couldn't be made. One possability is the cb is actually bouncing and comes down on the ob.
S
SuperDave
Guest
Can I strike the object ball twice? 
Skeezicks said:
Thanks. Cool shot. Once FL told me that a 90degree cut just looked that way, so not knowing, I now call it a right angle cut, which everybody seems to know what I am talking about.
With cb on the rail, that certainly does make this one a challenge, especially to an intermediate like me. I would probably cheat and use left top. A lot of folks do not like ie, but I kind of like it sometimes. I almost always use it on extreme cuts because of my lower ability than some folks here.<G>
Sorry if my drawing is not accurate but I have trouble drawing shots that are done by feel. it is something Like this.
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Laura
SuperDave said:Can I strike the object ball twice?
that don't look very easy either. Maybe the cb twice.
Seems the folks saying it can be done claim the hit has to be thicker and with some speed. Leads me to suspect the cb is bouncing. Would sure like to see it on slo-mo viedo.
here's another one
http://endeavor.med.nyu.edu/~wei/pool/9egg
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This is a 79 degree cut. It's roughly the same cut angle as the snooker table shot described by stevelomako in the "Ask Keith McCready" thread (cue ball on the 3 spot, OB on the 7 spot, cut OB to the left corner pocket). The snooker shot is roughly 2.7 times as difficult as this one due to the smaller balls and the greater distances between the CB and OB, and the OB and pocket (disregarding pocket size differences and rail bridging).
Don't worry about the scratch.
http://endeavor.med.nyu.edu/~wei/pool/9egg
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This is a 79 degree cut. It's roughly the same cut angle as the snooker table shot described by stevelomako in the "Ask Keith McCready" thread (cue ball on the 3 spot, OB on the 7 spot, cut OB to the left corner pocket). The snooker shot is roughly 2.7 times as difficult as this one due to the smaller balls and the greater distances between the CB and OB, and the OB and pocket (disregarding pocket size differences and rail bridging).
Don't worry about the scratch.
L
locki
Guest
hi all!
i posted this on another thread...anyway...lemme give a say on this topic...
as a man of science, technology and engineering, i say, again, i say that its impossible to pocket a ball exactly at 90 degrees, if someone thought he did it, it must be only at 89.9999999999 degrees...
why?
you cant defy the laws of nature, particularly in pool, physics.
lemme explain what happens in a 90-degree cut shot...
in the image attached here...
from the laws of physics and trigonometry:
lets say the red horizontal line is the x-axis, and the red vertical line is the y-axis.
assuming the cb (the lower ball) travels in the direction the arrow is pointing to, the path is exactly perpendicular (90 degrees) to the object ball, the contact point is the point where the blue and yellow line intersects, the angle between them is 90 degrees.(that is no matter how you made the cue ball travel in that direction, wheter you aim thicker on the object ball and apply left spin, or aim thinner and apply right spin, or dead straight)
for simplicity's purposes, lets say you applied 10 pounds of force to the cue ball, the amount of force that will be translated to the object ball would be equal to
10cos90 (10 pounds of force multiplied to the cosine of 90 degrees)
from your calculator, windows has a calculator, you can turn on its scientific functions if you dont have a scientific calculator,it would be equal to zero. meaning, the object ball doesnt receive any amount of force you applied on the cue ball.
this is assuming there's no friction on the table and the amount of force you implanted on the cb would still be the same the instant the cb hits the ob. otherwise, the force it carries is less than 10.
if you used english for the cb to move in the direction of the arrow, the effect on the cb would be, it would just be spinning/rotating in its place, throw wouldnt play a role in here because the ob didnt travel at all.
now lets say you did a not so perfect stroke, or aim, or you applied more or less side spin, resulting to a travel path of the cue ball 89.9999999 degrees with respect to the yellow line, the amount of force the object ball would be receiving would be equal to
10cos89.99
and that is equal to 1.7453292519943207159621337555219e-6 pounds of force which is a very small amount of force you would not really notice the ball actually moved.
i guess i dont need to mention this but, this is why the thicker you hit the ob, the more force it receives from the cb. at 90 degrees, the ob doesnt receive an amount of force.
so you cannot really move the ob if the angle is 90 or more, between the yellow line and the blue line.
i posted this on another thread...anyway...lemme give a say on this topic...
as a man of science, technology and engineering, i say, again, i say that its impossible to pocket a ball exactly at 90 degrees, if someone thought he did it, it must be only at 89.9999999999 degrees...
why?
you cant defy the laws of nature, particularly in pool, physics.
lemme explain what happens in a 90-degree cut shot...
in the image attached here...
from the laws of physics and trigonometry:
lets say the red horizontal line is the x-axis, and the red vertical line is the y-axis.
assuming the cb (the lower ball) travels in the direction the arrow is pointing to, the path is exactly perpendicular (90 degrees) to the object ball, the contact point is the point where the blue and yellow line intersects, the angle between them is 90 degrees.(that is no matter how you made the cue ball travel in that direction, wheter you aim thicker on the object ball and apply left spin, or aim thinner and apply right spin, or dead straight)
for simplicity's purposes, lets say you applied 10 pounds of force to the cue ball, the amount of force that will be translated to the object ball would be equal to
10cos90 (10 pounds of force multiplied to the cosine of 90 degrees)
from your calculator, windows has a calculator, you can turn on its scientific functions if you dont have a scientific calculator,it would be equal to zero. meaning, the object ball doesnt receive any amount of force you applied on the cue ball.
this is assuming there's no friction on the table and the amount of force you implanted on the cb would still be the same the instant the cb hits the ob. otherwise, the force it carries is less than 10.
if you used english for the cb to move in the direction of the arrow, the effect on the cb would be, it would just be spinning/rotating in its place, throw wouldnt play a role in here because the ob didnt travel at all.
now lets say you did a not so perfect stroke, or aim, or you applied more or less side spin, resulting to a travel path of the cue ball 89.9999999 degrees with respect to the yellow line, the amount of force the object ball would be receiving would be equal to
10cos89.99
and that is equal to 1.7453292519943207159621337555219e-6 pounds of force which is a very small amount of force you would not really notice the ball actually moved.
i guess i dont need to mention this but, this is why the thicker you hit the ob, the more force it receives from the cb. at 90 degrees, the ob doesnt receive an amount of force.
so you cannot really move the ob if the angle is 90 or more, between the yellow line and the blue line.
locki said:hi all!
i posted this on another thread...anyway...lemme give a say on this topic...
as a man of science, technology and engineering, i say, again, i say that its impossible to pocket a ball exactly at 90 degrees, if someone thought he did it, it must be only at 89.9999999999 degrees...
This is a very technical way of saying what FL told me. IMO right angle cuts are done with english for a reason. Never really thought of the physics but guess english changes the angle.
Laura
I
instroke
Guest
Skeezicks said:
All I have to say is that anyone on earth can come to Russelville Arkansas and bet a suitcase full of cash on this shot. I defy anyone to make it with a level cue. Unless the approach angle is changed I firmly believe that this shot is impossible and I'll pay to see it.
John