See? Still with the odds. In a perfect scenario, the player will be guessing both times and worse compelled by a fixed condition to undo the first guess. Playing the 66% might do more to alleviate anxiety than actually winning the car.You’re completely missing the point and the math
The odds of picking correctly the first time is 1 in 3
It doesn’t change if you do not make the switch. It only changes if you do
That’s why the switch is mandatory to improve the odds
Anything short of STFU Noob is accepted here.Can I answer that?![]()
I think there was a card game like this that some guy hustled a lot of people in the old west with. I think it was different than three card Monte because I think Three card Monte is about the sleight of hand and this is about very unintuitive odds.I’ve literally only robbed two guys of 20 bucks on this but I think it’s pretty fun.
But what if I have a car and need a goat?You’ll see the only time you “lose” when swapping doors is when both of the doors you didn’t choose are goats.
That's always been the most effective way of comprehending the problem for me. When you accept that 999 times out of 1000 the car is not behind your door and then remove the other places where the car isn't, it becomes a little more understandable. It's funny to watch the people arguing against the mathematicians.For those having a hard time grasping why you should switch doors, imagine that instead of 3 doors there are 1,000 doors, with 999 goats and one car. The host knows where the car is, and asks you to pick a door. After you pick a door he opens up all but one of the remaining doors, revealing 998 goats. There are two doors left, the one you initially chose, and the one he didn't open.
Should you stay with your original choice or switch to the door he didn't open?
To me, the easiest way to understand the conundrum of the Monty Hall problem is to assume the same game, but with 100 doors instead of 3 doors, with the car behind only one of those 100 doors and a goat behind the other 99 doors.The easiest explanation:
You pick wrong 66% of the time.
Which means Monty has the car in one of those doors 66% of the time.
But, it says he knows where it is. Which means he never opens the car door and he has the car 66% of the time.
So, you use this knowledge to your advantage and flip the odds in your favor because he always opens a door with a goat.
I can “shake the red card” pretty good. Not as good as I could back when I practiced it all the time. It’s not hard to do, with a few hours of practice, to really pull it off takes much longer. It’s impossible to tell when someone is real good at it. If they are working with a crew, it’s impossible to beat. Because if the mark does pick the winning card, someone from the crew will place a higher bet on the wrong card-the dealer only takes the high bet, which knocks the marks correct winning bet. Follow that?I think there was a card game like this that some guy hustled a lot of people in the old west with. I think it was different than three card Monte because I think Three card Monte is about the sleight of hand and this is about very unintuitive odds.
A guy showed me how the card work is done but the schill work does lock it up. Thanks for that revelation.I can “shake the red card” pretty good. Not as good as I could back when I practiced it all the time. It’s not hard to do, with a few hours of practice, to really pull it off takes much longer. It’s impossible to tell when someone is real good at it. If they are working with a crew, it’s impossible to beat. Because if the mark does pick the winning card, someone from the crew will place a higher bet on the wrong card-the dealer only takes the high bet, which knocks the marks correct winning bet. Follow that?
In other words you have 0% chance to win in 3 card Monte against a crew. I’ve worked in those crews. I’d have never mentioned this in the past. But that hustle like most are in the past as the secret is all over the interwebs destroying all hustles
Fatboy<———back to the drawing board…..
I never minded letting 3 card Monte take a couple of bucks. Dude has developed a skill. At least he's not just begging or stealing. Those guys were entertainers.I can “shake the red card” pretty good. Not as good as I could back when I practiced it all the time. It’s not hard to do, with a few hours of practice, to really pull it off takes much longer. It’s impossible to tell when someone is real good at it. If they are working with a crew, it’s impossible to beat. Because if the mark does pick the winning card, someone from the crew will place a higher bet on the wrong card-the dealer only takes the high bet, which knocks the marks correct winning bet. Follow that?
In other words you have 0% chance to win in 3 card Monte against a crew. I’ve worked in those crews. I’d have never mentioned this in the past. But that hustle like most are in the past as the secret is all over the interwebs destroying all hustles
Fatboy<———back to the drawing board…..
Say it's life or death. Would you play?
One schill can lock it up 100%A guy showed me how the card work is done but the schill work does lock it up. Thanks for that revelation.
That’s a 1000% rightI never minded letting 3 card Monte take a couple of bucks. Dude has developed a skill. At least he's not just begging or stealing. Those guys were entertainers.
No, it shows (not presumes) your first pick has half as much chance of being right as if you switch - that’s not “always wrong”, just twice as often.The math presumes or rather is interpreted as 'your first pick will always be wrong'.
As has been said a number of times, 1 in 3 without switching vs. 2 in 3 switching.What are the odds a person will get the car on one attempt both with and without the "required" switch?
That’s a pretty big bet. I’m down!A more proper example would be:
You have no choice to play and it’s life or death.
Do you switch doors?
In that scenario, you double your chances of living by switching doors.
Ok. The language is more compelling that way.
But, broken record time again, The math presumes or rather is interpreted as 'your first pick will always be wrong'.
What are the odds a person will get the car on one attempt both with and without the "required" switch?
So, exactly the same situation with a gun instead of a car - so you’d better switch.Let’s make it life or death. You have no choice. You have to play the game. Let’s say the Jigsaw killer said “let’s play a game.”
-There are 3 doors. Behind one of them is a gun that kills you if you open that door. There is nothing behind the other two doors.
-You have to pick a door randomly, that won’t be opened yet.
-You pick your door.
-Monte gets to look inside the other two doors. He absolutely must open a door that’s empty,
-That means if both doors are empty, he can open either one. If one door has the gun, he has to open the empty door.
-He opens a door and it’s empty (this happens 100% of the time)
-Now, you have a choice to open your door, or his door.
Which door do you open?
You asking me? I do not know. Yeah yeah, the odds say...Let’s make it life or death. You have no choice. You have to play the game. Let’s say the Jigsaw killer said “let’s play a game.”
-There are 3 doors. Behind one of them is a gun that kills you if you open that door. There is nothing behind the other two doors.
-You have to pick a door randomly, that won’t be opened yet.
-You pick your door.
-Jigsaw gets to look inside the other two doors. He absolutely must open a door that’s empty,
-That means if both doors are empty, he can open either one. If one door has the gun, he has to open the empty door.
-He opens a door and it’s empty (this happens 100% of the time)
-Now, you have a choice to open your door, or his door.
Which door do you open?