Another situation comes up when not playing even. Example, playing 8-7.....
Each player needs 1 ball (7-6). Two balls on the table. If a player makes his ball AND the opponemts ball on the same shot, the game goes to the shooter.
Troy [/B][/QUOTE]
That has never come up for me, Troy, but where did you get that rule? I tend to agree with it. It makes more sense than the one that I have heard, which is game goes to the first ball that dropped. Now that could make for an ugly argument. It's amazing as many games as I've played that it's never happenned.
Each player needs 1 ball (7-6). Two balls on the table. If a player makes his ball AND the opponemts ball on the same shot, the game goes to the shooter.
Troy [/B][/QUOTE]
That has never come up for me, Troy, but where did you get that rule? I tend to agree with it. It makes more sense than the one that I have heard, which is game goes to the first ball that dropped. Now that could make for an ugly argument. It's amazing as many games as I've played that it's never happenned.