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ForumGhost516

AzB Silver Member
Silver Member
Ok so here is the situation two players are playing and there are two balls left on the table. Player A shoots at one and scratches however the object ball and the 15th ball both end up behind the headstring. What happens since I was taught you could not shoot back at the two balls.

Please let me know asap!!

Charlie
 
Reply

When a player has the cue ball in hand behind the head string (as after a scratch) and all the object balls are behind the head string, the object ball nearest the head string may be spotted upon request. If two or more balls are an equal distance from the head string, the player may designate which of the equidistant balls is to be spotted.

Andy
 
the specific rule under the World Standardized Rules of the World Pool Association, under General Rules
www.wpa-pool.com

direct link..
http://wpa-pool.com/index.asp?content=rules_tournament

1.5 Cue Ball in Hand
When the cue ball is in hand, the shooter may place the cue ball anywhere on the playing surface (see 8.1 Parts of the Table) and may continue to move the cue ball until he executes a shot. (See definition 8.2 Shot.) Players may use any part of the cue stick to move the cue ball, including the tip, but not with a forward stroke motion. In some games and for most break shots, placement of the cue ball may be restricted to the area behind the head string depending on the rules of the game, and then 6.10 Bad Cue Ball Placement and 6.11 Bad Play from Behind the Head String may apply.
When the shooter has the cue ball in hand behind the head string and all the legal object balls are behind the head string, he may request the legal object ball nearest the head string to be spotted. If two or more balls are equal distance from the head string, the shooter may designate which of the equidistant balls is to be spotted. An object ball that rests exactly on the head string is playable.
 
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