Patrick,
Thanks for defining the terms. That does show where our differences come about. The logic that leads to the addition of one ball diameter to the edge-edge distance, as opposed to one radius or three radii is impeccable, if I may judge, given the definitions you presented. But I think we have to look at those definitions.
Patrick Johnson said:
Aim Line = a line extended from the tip/CB contact point to the edge of the object ball. [With the CB's stripe oriented along the Aim Line as you suggest, Tip Offset also = the apparent distance from the CB's "surface center" to the edge of the stripe, viewed from the perspective of a shooter facing along the Aim Line, so the tip/CB contact point should be on the edge of the CB's stripe.]
I'm not sure what "Tip Offset also = ...." means here, but I don't think it's important.
Patrick Johnson said:
Tip Offset = the distance from the CB's center-of-mass ("peach pit center") to the Aim Line measured along a line perpendicular to the Aim Line.
Agreed. We might distinguish between the apparent tip offset, b, which is the offset of the center of the shaft, and the offset of the actual contact point, b'. Note: in your current diagram, the offset b' is a little bit larger than (1/2)R since the stripe's edge is not pointing at the OB's edge.
Patrick Johnson said:
CB Path = the line-of-centers between CB and OB when the Aim Line is correctly adjusted for squirt (the CB's intended path).
Agreed.
Patrick Johnson said:
Pivot Length = the distance the cue ball travels along the CB Path before diverging from the Aim Line by the amount of the Tip Offset.
This is the crux of the issue. I've used this definition at times, but it is incompatible with the standard definition.
Let me repeat the aim-and-pivot defintion, used by Bob Jewett, Ron Shepard, and Dr. Dave Alciatore, amongst others. This is the most natural one as it goes directly to how you use it. To wit: line up for center ball and then pivot about the PP. After shooting in the new direction, the cueball will travel in the same direction as when lined up for centerball. I'm pretty certain you completely agree with this, but I just wanted to put it out there.
Given that, in order for the cueball to diverge from the aim line direction by an amount equal to the tip offset, it must travel a distance along the line of centers which depends on which offset we're talking about, b or b'. In the case of b (offset of center of shaft), this will be the pivot length P plus one ball radius. In the case of b' (offset of contact point), this will be the same distance (P + R) multiplied by a factor which depends on the tip's radius of curvature. (If you can abide it, the factor is R/(R +r), where r is the tip's radius. Using 13/32" for an approx. nickel radius, and R =1.125", the factor is .7347.)
So, you get significanlty different results depending on which offset you use.
Using the center of the shaft at a (1/2)R offset, and pointing it toward the edge of object ball, the cueball travels (P + R) - 2R before colliding withe OB. The -2R comes from the necessary separation at collision, as per your argument. Since P + R - 2R = P - R, we must add R, and only R, to the edge to edge travel distance to get P.
Using the actual contact point offset at (1/2)R, the cueball travels .7347(P + R) - 2R before colliding. There's no way to extract P from this by adding any integral multiple of R to it. You'd have to add (2 - .7347)R, then multiply by 1/.7347, assuming of course that the tip's radius is 13/32".
How does any of this sound? (Could be I've gone completely nuts somewhere along the way.)
Jim