Pubo
Active member
If you open your Fargo app and click on the "FIND RACE" button, you can calculate the odds of winning given two players Fargo, but the app doesn't tell you how this is calculated.
Here is what I found: as long as the scores difference is 332 (say 732 vs. 400), the higher-rated player has a 90.9% to 9.1% chance of winning 1 match.
If you take this a step further, and have a match between a 400+332+332 = 1064 (I know nobody on Earth has a Fargo this high, but let's assumed so) vs a 400, then the chance (of winning one match) becomes 99% to 1%.
This suggests that the chance of winning increases 10-fold as your score difference increases by 332. This is a standing assumption of the Fargo system: that if you are 10 times as likely to beat player A, and player A is 10 times as likely to beat player B, then you are 100 times as likely to beat player B. This is not true in real world, but I guess this is a good enough assmption.
So the relationship is logarithmic. If your Fargo is M and your opponent's O, then your chance of winning one rack is
I remember reading an article from FargoRate, and they said that they changed their rating system away from ELO, but this seems to be exactly the same as the ELO system, but just with a different number (400 for ELO, 332 for Fargo) which is widely used in chess.
Here is what I found: as long as the scores difference is 332 (say 732 vs. 400), the higher-rated player has a 90.9% to 9.1% chance of winning 1 match.
If you take this a step further, and have a match between a 400+332+332 = 1064 (I know nobody on Earth has a Fargo this high, but let's assumed so) vs a 400, then the chance (of winning one match) becomes 99% to 1%.
This suggests that the chance of winning increases 10-fold as your score difference increases by 332. This is a standing assumption of the Fargo system: that if you are 10 times as likely to beat player A, and player A is 10 times as likely to beat player B, then you are 100 times as likely to beat player B. This is not true in real world, but I guess this is a good enough assmption.
So the relationship is logarithmic. If your Fargo is M and your opponent's O, then your chance of winning one rack is
I remember reading an article from FargoRate, and they said that they changed their rating system away from ELO, but this seems to be exactly the same as the ELO system, but just with a different number (400 for ELO, 332 for Fargo) which is widely used in chess.