Have some questions on 9 ball spots. Recently started a BCA league that is handicapped. Saw a spot that was the 8 and the last 3. I guess I don't understand that spot, as the 8 is always part of the last 3 balls. When you give someone the last 3 is it implied that they have to run to the 7 and make it (assuming the 7 and 8 are on the table) and can't combo the 7 or 8 in early? I saw the other thread where someone says the 8 is the stronger spot when compared to the last two. I would have thought the last 2 would be a better spot. TIA
9 ball spots?
- Thread starter drv4
- Start date
Think it through. What if the 8 goes in on the break? Is it still part of the last 3 balls? What if the first shot of the rack is a 1-8 combo?
The last X means *whatever* X balls are left on the table, if you make one of those legally you win the game. Sometimes particular balls go on the break, and certain combos are made, so that the last 3 are the 1-2-9.
If you get the 8 ball, you win when you legally make the 8 ball. Usually it is specified whether or not it counts on the break, whether or not it is called or wild, where it has to be racked, etc. Same thing as the 7 ball, 4 ball, whatever.
So the 8 and the last 3 means you win the game if either 1) The 8 is made legally. 2) One of the last 3 balls on the table is made legally, or of course 3) the 9 is made legally.
Everything here pertains to 9 ball.
So for example: I break and make the 2 and 7 on the break. Now remaining is the 1-3-4-5-6-8-9. I run the 1,3,4 and 5. Now remaining on the table is the 6-8-9. If I make the 6 (or the 8 or 9) I win. Another example: My opponent breaks and breaks dry. There is a 2-8 combo hanging. If I legally make it, I win. That is why the 8 *and* the last three is different than just the last 3.
Hope this helps.
KMRUNOUT
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Thanks KM, that does help. I guess I misinterpreted someone getting the last 3 as meaning if I break dry and then they come to the table and shoot the 1-7 combo they would win since the 7,8 and 9 are the last three balls that would need to be shot. I didn't take it literally enough to mean that the last three is literally the last three balls left when the other six are made.
The 8 is not always one of the last three balls on the table.
the 8 is always a stronger than the last 2. as the weaker player can win early with a combine on the 8 or 9. as for the 8 & the last 3, if the 8 is made early by the stronger player then the weaker player still has the remaining 2 highest numbered balls in addition to the 9 ball