hi all, ive just read the thread up to page 5, i might have overlooked some things...anyway...lemme give my pov...
FIRST
the ghost ball aiming is not wrong, its only not 100% perfect. yes, serious pool players noobs use this thing, some dont even know that they use it (like me back then). i have developed and honed my skills around this system. i said it isnt 100% perfect but as you use it, you learn to adapt to its flaws, and thus you make necessary adjustments to compensate its flaws, like in what is discussed here, throw.over time, as you practice, you somehow leve religiously to what happens to each and every single situation you encounter, and its deviations. im talking here of billions and billions of deviations. its like life, you'll learn to adapt to it and make the best out of it. its hard but its how i learned how to play pool at a higher level.
i use the gb to aim, and play by feel if needed. usually playing by feel comes after thousands of hours of practice and experience fyi.
SECOND
as a man of science, technology and engineering, i say, again, i say that its impossible to pocket a ball exactly at 90 degrees, if someone thought he did it, it must be only at 89.9999999999 degrees...
why?
you cant defy the laws of nature, particularly in pool, physics.
lemme explain what happens in a 90-degree cut shot...
in the image attached here...
from the laws of physics and trigonometry:
lets say the red horizontal line is the x-axis, and the red vertical line is the y-axis.
assuming the cb (the lower ball) travels in the direction the arrow is pointing to, the path is exactly perpendicular (90 degrees) to the object ball, the contact point is the point where the blue and yellow line intersects, the angle between them is 90 degrees.(that is no matter how you made the cue ball travel in that direction, wheter you aim thicker on the object ball and apply left spin, or aim thinner and apply right spin, or dead straight)
for simplicity's purposes, lets say you applied 10 pounds of force to the cue ball, the amount of force that will be translated to the object ball would be equal to
10cos90 (10 pounds of force multiplied to the cosine of 90 degrees)
from your calculator, windows has a calculator, you can turn on its scientific functions if you dont have a scientific calculator,it would be equal to
zero. meaning, the object ball doesnt receive any amount of force you applied on the cue ball.
this is assuming there's no friction on the table and the amount of force you implanted on the cb would still be the same the instant the cb hits the ob. otherwise, the force it carries is less than 10.
if you used english for the cb to move in the direction of the arrow, the effect on the cb would be, it would just be spinning/rotating in its place, throw wouldnt play a role in here because the ob didnt travel at all.
now lets say you did a not so perfect stroke, or aim, or you applied more or less side spin, resulting to a travel path of the cue ball 89.9999999 degrees with respect to the yellow line, the amount of force the object ball would be receiving would be equal to
10cos89.99
and that is equal to 1.7453292519943207159621337555219e-6 pounds of force which is a very small amount of force you would not really notice the ball actually moved.
i guess i dont need to mention this but, this is why the thicker you hit the ob, the more force it receives from the cb. at 90 degrees, the ob doesnt receive an amount of force.
so you cannot really move the ob if the angle is 90 or more, between the yellow line and the blue line.