How does loser break favor weaker players?
In order for the break to count for something you need to be consistently able to run tables, break nines, or play lock-up safes.
If you are and your opponent is not (by virtue of being the weaker player), then how is his breaking and maybe making a couple of balls any detriment to your chances of winning?
As for ruining the momentum, the loser could just as easily do that by taking a long time to rack, racking badly on purpose, etc.. I guess this is negated by rack-your-own, tho.
I guess what I am saying is that if you get a single turn, with a shot at the table during the game, then the break is negated. If you don't, then you probably aren't playing a 'weaker' player.
The most obvious reason is that it gives the loser a chance to shoot where he would not have gotten one. The winner may have run the first 3 racks and then played safe. So the difference would be the opponent coming up to shoot with ball in hand and the break with a score of 1-0, OR coming to the table hooked behind a blocking ball with a low percentage kick and a score of 3-0! ( soon to be 4-0 with the winner breaking again).
Can you not see a HUGE difference in the 2 possbilities?
Also it is a tournament setting, so taking many long breaks to pull your opponent out of stroke is not going to happen. And about the racks, if you are getting bad racks, you need to check them first, or rack your own.
The point is, under winner breaks, you are not gauranteed a shot EVER! If you are playing a strong player who is on a roll, they can torture you relentlessly. You KNOW that any mistake can result in a MULTIPLE game changing score. In loser breaks, you ARE gauranteed at least a chance out of every 2 games. The only way you will not shoot in a given game is if you won a rack and your opponent gets the next break and runs out. Then it will be your break again.
Now if neither player can run out, then it is not much of a game decider. The higher the level of play, the more important it becomes.
Ball in hand every shot is a HUGE spot, but not if the player getting it cannot run 3 balls ever! See what I mean? It is still a huge spot, but if you are not at a level to really take advantage, it really won't matter.
If you watch good players, ONE missed shot or safe will mean the rack ( and possibly many more under winner breaks rules). BUT, if you are watching 2 bangers, they can each take 4 shots a piece on the 7, 8, and the 9. The winner is ALWAYS up for grabs till the last ball drops.
This discussion was in the context of a higher level tournamnet, NOT 2 bangers on a bar box. These are 2 completely different animals.
Regardless of skill level, are you more likely to win a given game or match with one opportunity or several? Okay, HOW ABOUT NONE? The bottom line is that in loser breaks, the weaker player will have more chances to make something happen. That does not mean he will be successful, just that he will have more opportunitues to be. Though if this player can't win with 10 opportunities, I do not think he would do BETTER with 3 chances.
EDIT- To your main point: Obviously if the skill level difference is HUGE than you will still win under just about any rules/handicap. If I play someone who can't run 3 balls, I could spot them 4 games in a race to 7 and give them ball in hand every shot and the breaks, and still win! That does not mean that the game did NOT favor the weaker player! It obviously greatly favored the weaker player. It just did not favor him ENOUGH.
When the skill level between 2 players is close, you may be very suprised what seemingly minor thing can tip the game to one's favor. And EXTRA chances in this situation is NOT a minor thing!
Jw