SORRY, IT'S 13:2 NOT 14:2! 
Just the other night, me and my friend were starting to play some 9 or 10 ball, but he randomly suggested a whole new game that he just made up.
To make it easy and clear, here are the rules:
* Played with 13 balls, racked liked an 8-ball rack, two corner balls are missing, 13 in the middle. 1 in front and other numbers randomly.
* After your turn comes, you can shoot TWO different balls, ALWAYS. These two different balls must be the two lowest numbered balls on the table.
* Call shot, pocket, call safe game.
* Who ever pockets the 13-ball as the last ball of the rack, wins.
* You can shoot 13-ball into the pocket with a combo or a carom(called ofcourse), but it spots and you can continue shooting.
* If there are only two balls left on the table, one being 13-ball, and the second whatever is left, then you can still shoot the 13-ball into the pocket first, it respots, and you will have a choice once again to shoot whichever ball. This can be used a maximum of 3 times, after you have shot the 13-ball into the pocket 3 times, it still respots, but then you must shoot the lowest numbered ball on the table.
* If you pocket the 13-ball on the break, it respots, and you can continue shooting, but it only then respots if it doesn't block either of the two lowest numbered balls. We use the "free ball" rule as known in snooker.
* If a foul is made, opponent gets cueball in hand anywhere on the table, also after a break foul.
Think I've covered it.
Let me know if you have played something like this before. We liked it a lot. To me it seems like a combination of 10 and 8 ball. You can constantly play postion for two balls, yet it requries some solid shotmaking skills.
The runout is a lot easier than in 10-ball, which makes it fun for players who struggle with 10-ball runouts.
Cheers!
Just the other night, me and my friend were starting to play some 9 or 10 ball, but he randomly suggested a whole new game that he just made up.
To make it easy and clear, here are the rules:
* Played with 13 balls, racked liked an 8-ball rack, two corner balls are missing, 13 in the middle. 1 in front and other numbers randomly.
* After your turn comes, you can shoot TWO different balls, ALWAYS. These two different balls must be the two lowest numbered balls on the table.
* Call shot, pocket, call safe game.
* Who ever pockets the 13-ball as the last ball of the rack, wins.
* You can shoot 13-ball into the pocket with a combo or a carom(called ofcourse), but it spots and you can continue shooting.
* If there are only two balls left on the table, one being 13-ball, and the second whatever is left, then you can still shoot the 13-ball into the pocket first, it respots, and you will have a choice once again to shoot whichever ball. This can be used a maximum of 3 times, after you have shot the 13-ball into the pocket 3 times, it still respots, but then you must shoot the lowest numbered ball on the table.
* If you pocket the 13-ball on the break, it respots, and you can continue shooting, but it only then respots if it doesn't block either of the two lowest numbered balls. We use the "free ball" rule as known in snooker.
* If a foul is made, opponent gets cueball in hand anywhere on the table, also after a break foul.
Think I've covered it.
Let me know if you have played something like this before. We liked it a lot. To me it seems like a combination of 10 and 8 ball. You can constantly play postion for two balls, yet it requries some solid shotmaking skills.
The runout is a lot easier than in 10-ball, which makes it fun for players who struggle with 10-ball runouts.
Cheers!
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