PKM said:
It's over my head, but if no one has linked it yet, here is Dr. Dave's technical proof
http://www.engr.colostate.edu/~dga/pool/technical_proofs/new/TP_A-14.pdf
I haven't read his work, but have watched his videos,
which are flawed.
mike,
I don't think your analogy fits here.
we're talking about one spinning object contacting
one static object.
The spinning object also has velocity, this velocity is
transferred, as well as the spin (to some small degree).
Doesn't it make sense that since the spin on the CB doesn't
affect it's rebound angle, or tangent, then the OB's trajectory
will be affected by the spin in the same way?
none.
If there were significant friction between the two, shouldn't
both be affected similarly?
If it's not possible to pull the CB off of the tangent line using side
how is it possible that the OB will act otherwise?
Shouldn't it be easier to show some change in the tangent line w/ side
since we're imparting so much more onto the CB than the CB imparts
onto the OB?
Would this be known as OB deflection?
Is there a way to correct this OB deflection?
Wouldn't this OB deflection only be present in an off center hit(cut shot)
the same way that the CB is affected by striking it with the cue stick
off center?