Scratched on 100 :(

[TheOne]

I hadn't played for 6 days due to illness and NYE but had another hit yesterday. I borrowed the usual cue or so I thought and ran 50 something first visit before missing. I carried on and ran 5+ 6 racks before scratching after making a ball and breaking up a small cluster of 2. There was 3 balls left on the table and for 30 minutes I thought I'd scratched on 99 lol, but I was adding the last rack up as 14 doh!

Anyway 5 + 6 racks(84) + 11 = 100 I hope!

If I get chance I'll try and wei what happened

 

[Jason Robichaud]

Hey, I know the answer to this one now...
s + (x * 14) + (15 - y) = z

5 + (6 x 14 = 84) + (15-3= 12) = 101... I guess I have to take 1 away because of the scratch and then your point deduction (what ever that is) so 100 minus foul.

Damn, I was hoping to run 100 before I figure out how to keep score.

Great run!

 

[terhje]

nice run

it will look good at the AZstraightpool list

5
19
33
47
61
75
89
103
4 (the ball you pocketed comes up.. or was it already spotted when it was 3 left on the table?).

the ball dosent count ..it makes it 99. + a minus?
gets to 98??

and if it was already spottetd 99.


or am i totaly wrong?? :smile:

 

[mjantti]

Nasty if that's 99, man... But it seems you're shooting 'em straight, keep going. Oh, I remember the good ol' days when I was able to beat you...

 

[Steve Lipsky]

Glad to hear you're back and shooting well, Craig! Looking forward to more participation in the forum this year, sir.

- Steve

 

[mjantti]

it will look good at the AZstraightpool list

5
19
33
47
61
75
89
103
4 (the ball you pocketed comes up.. or was it already spotted when it was 3 left on the table?).

the ball dosent count ..it makes it 99. + a minus?
gets to 98??

and if it was already spottetd 99.


or am i totaly wrong?? :smile:

5 on the table, on 7th rack the "table counter" stands for 5+(7*14) = 103, you scratch while 3 balls on the table, your run is (103-3)-1=99. Sorry Craig, that's exactly 99. You should've just make a legal shot on the 101th ball to make sure of the 100 On the other hand, if you'd been in a tournament with a race to 100, you would have never had to shoot the 101th ball and your run would've been exactly 100.

Edit: You always bring 14 balls to the table between racks, you never add 15. You might start with 15 balls though...

 

[TheOne]

5 on the table, on 7th rack the "table counter" stands for 5+(7*14) = 103, you scratch while 3 balls on the table, your run is (103-3)-1=99. Sorry Craig, that's exactly 99. You should've just make a legal shot on the 101th ball to make sure of the 100 On the other hand, if you'd been in a tournament with a race to 100, you would have never had to shoot the 101th ball and your run would've been exactly 100.

Edit: You always bring 14 balls to the table between racks, you never add 15. You might start with 15 balls though...

Ha thanks for all the comments!

I'm pretty sure it was 100 though, I started with 5 balls then ran 6 full racks = 89 (6 * 14 = 84).

In the last rack I made 12 balls but because I scratched on last ball it was only 11.

Therefore 100

 

[Mike_Mason]

Sorry to say it's 99...

You run 5 balls...then continue to run 84 (6 full racks)...at this point you are on a run of 89...

You break open the next rack and run 11...and if the owner tells you that he is now closed and everyone has to leave then you could say that you ran 100 balls...on an unfinished run...but...

The game is 14.1 Continuous...you continued your play and on the next shot you pocketed a ball and scratched.

The object ball that you made does not count because you scratched while making it...and you lose a point for the scratch.

Final run = 99 balls.

Great run but better luck next time...

Mike

 

[Steve Lipsky]

I think it's a 100. There is a distinction between a run and the score. It is a run of 100 with a separate 1 point penalty. The penalty goes against the score, not the run.

Another way to look at it might make it easier to see. Let's say I have a score of 20. With an open table, I run 5. I scratch on the 6th shot. I will remove a bead from the 20, so my score goes down to 19. I will then move over 5 beads to represent my run of 5. My total score as of this moment is 24.

People who think Craig ran 99 here are effectively saying that in the above example, the score of 20 would remain, and the player would move over only 4 balls. They would say my run was only 4. This would still equate to 24 (the right score), but it's not represented correctly. There would only be 4 beads in the rack score, when really there are 5 balls down.

So if we concur that 5 beads must slide over, not 4, then I don't see how there can be a disagreement. You can't look at 5 beads and say one of them doesn't count. I mean, I guess you can, but I don't think it's accurate.

- Steve

 

[Marop]

I think it's a 100. There is a distinction between a run and the score. It is a run of 100 with a separate 1 point penalty. The penalty goes against the score, not the run.

Another way to look at it might make it easier to see. Let's say I have a score of 20. With an open table, I run 5. I scratch on the 6th shot. I will remove a bead from the 20, so my score goes down to 19. I will then move over 5 beads to represent my run of 5. My total score as of this moment is 24.

People who think Craig ran 99 here are effectively saying that in the above example, the score of 20 would remain, and the player would move over only 4 balls. They would say my run was only 4. This would still equate to 24 (the right score), but it's not represented correctly. There would only be 4 beads in the rack score, when really there are 5 balls down.

So if we concur that 5 beads must slide over, not 4, then I don't see how there can be a disagreement. You can't look at 5 beads and say one of them doesn't count. I mean, I guess you can, but I don't think it's accurate.

- Steve

Steve you are 100% correct, the run has nothing to do with the continious score, an inning is an inning, you pay the penalty on the run when you spot the ball you made when you scratched. The second penalty is loss of a point from your previous score, even if you start from
zero.

Craig's inning at the table was 100.

Nice run mate...


Bill

 

[Mike_Mason]

This is interesting...we are definitely splitting hairs here...but it's an important hair...a 100 ball run is THE yardstick in straight pool.

And anyone that can run 99 has in the past or will surely in the future run more than 100...and for the record I have a 99-ball run lol...

If the match were being scored on paper...inning by inning...the score for that inning would be 99...

And Steve, as for beads...imo this confuses things not clears them up...they are visual tools and not official inning scores...

In your example, I agree that when your shooter is done with his inning...he has 19 beads on the total that used to be 20...and 5 beads for the current rack...

I am not ignoring the 5 beads on the wire for the current rack but we can't ignore that there are now 19 beads where before the shot there were 20...all of which are considered in the current inning...which if there were an official scoresheet the inning score would be marked 4 and not 5.

The penalty is a part of the run.

Mike

 

[Marop]

This is interesting...we are definitely splitting hairs here...but it's an important hair...a 100 ball run is THE yardstick in straight pool.

And anyone that can run 99 has in the past or will surely in the future run more than 100...and for the record I have a 99-ball run lol...

If the match were being scored on paper...inning by inning...the score for that inning would be 99...

And Steve, as for beads...imo this confuses things not clears them up...they are visual tools and not official inning scores...

In your example, I agree that when your shooter is done with his inning...he has 19 beads on the total that used to be 20...and 5 beads for the current rack...

I am not ignoring the 5 beads on the wire for the current rack but we can't ignore that there are now 19 beads where before the shot there were 20...all of which are considered in the current inning...which if there were an official scoresheet the inning score would be marked 4 and not 5.

The penalty is a part of the run.

Mike

The inning was 100.

At the DCC straight pool championship last year, which was conducted by Bob Jewett who knows the rule book in and out, Thorsten ran 98 3 times in a row and scratched on the breakball (the 99th ball) all three times his inning was scored as 98 not 97.

If this was a match the penalty would have been taken off of his previous score and the inning would have been marked up as 98.

 

[TheOne]

didn't mean to cause so much confusion!

But with regards to this list pretty sure it's 100, interesting points though. Basically I ran 100 balls and fouled on 101st which doesn't count.

 

[mjantti]

I'm pretty sure it was 100 though, I started with 5 balls then ran 6 full racks = 89 (6 * 14 = 84).

In the last rack I made 12 balls but because I scratched on last ball it was only 11.

Therefore 100

Nope. You make an error thinking you started with a run of 5 balls. What you do is you start by running 4 balls, then add 14 balls to the table and therefore the first breakball you have is not part of the first rack, it's part of the 2nd rack. Therefore you count it twice with your logic.

But I will gladly give you the 100, at least it was made in some stage of the run... let's just forget the foul

Marop says "At the DCC straight pool championship last year, which was conducted by Bob Jewett who knows the rule book in and out, Thorsten ran 98 3 times in a row and scratched on the breakball (the 99th ball) all three times his inning was scored as 98 not 97."

This has got nothing to do with the rulebook. In this tournament they chose not to count fouls within the run. In tournament play, if Craig's inning doesn't end the match, he scores exactly 99 points with his inning, with a 100 run and a 1 point penalty. If Craig needs exactly 100 points to win, he wins because he never has to take the 101th ball.

I think our AzB challenge should be called a "run challenge" and not an "inning challenge", it's just semantics but could be worth 1 point in your entry

 

[Steve Lipsky]

Nope. You make an error thinking you started with a run of 5 balls. What you do is you start by running 4 balls, then add 14 balls to the table and therefore the first breakball you have is not part of the first rack, it's part of the 2nd rack. Therefore you count it twice with your logic.

But I will gladly give you the 100, at least it was made in some stage of the run... let's just forget the foul

Marop says "At the DCC straight pool championship last year, which was conducted by Bob Jewett who knows the rule book in and out, Thorsten ran 98 3 times in a row and scratched on the breakball (the 99th ball) all three times his inning was scored as 98 not 97."

This has got nothing to do with the rulebook. In this tournament they chose not to count fouls within the run. In tournament play, if Craig's inning doesn't end the match, he scores exactly 99 points with his inning, with a 100 run and a 1 point penalty. If Craig needs exactly 100 points to win, he wins because he never has to take the 101th ball.

I think our AzB challenge should be called a "run challenge" and not an "inning challenge", it's just semantics but could be worth 1 point in your entry

Mikko, you must remember that not everyone uses the loony European way of scoring straight pool . Even though Craig is European, lol, I will give him the benefit of the doubt that when he said "started with 5 balls", he meant he pocketed 5 balls, then took a break ball into the 2nd rack. Not that when he started, there were 5 balls on the table, of which he pocketed 4 and then broke.

If I'm wrong, and Craig got to the table with only 5 balls on it, then Mikko's point is valid and the run is only 99.

- Steve

 

[mjantti]

Mikko, you must remember that not everyone uses the loony European way of scoring straight pool . Even though Craig is European, lol, I will give him the benefit of the doubt that when he said "started with 5 balls", he meant he pocketed 5 balls, then took a break ball into the 2nd rack. Not that when he started, there were 5 balls on the table, of which he pocketed 4 and then broke.

If I'm wrong, and Craig got to the table with only 5 balls on it, then Mikko's point is valid and the run is only 99.

- Steve

Steve, you're absolutely correct ! We use the (correct/perfect/excellent/exquisite ) scoring system here and we always start with a certain number of balls on the table which got me confused. If Craig started his run with 6 balls on the table, he ran 101 but his inning was an exact century. Very good point

Let's not start with scoring systems here, we've been down that road before.

 

[sjm]

This was a 100 ball run. That the trip to the table netted just 99 doesn't mean that Craig didn't run 100 consecutive balls.

This debate brings to mind the sad story of Dave Hampton of the NFL's Atlanta Falcons. In the final game of the season (early 1970's), Hampton became the first ever Atlanta Falcon to rush for 1,000 yards. The game was stopped, and the game ball was given to Hampton as a memento of his great accomplishment. Unfortunately, he lost yardage on a subsequent carry and finished the season with less than 1,000 yards rushing.

Pool isn't football, though. A guy who makes 100 consecutive shots has run a 100.

 

[TheOne]

Steve, you're absolutely correct ! We use the (correct/perfect/excellent/exquisite ) scoring system here and we always start with a certain number of balls on the table which got me confused. If Craig started his run with 6 balls on the table, he ran 101 but his inning was an exact century. Very good point

Let's not start with scoring systems here, we've been down that road before.

I think mjantti knows I haven't a clue how the Euro scoring system works as I had to let him score keep when we played!

I only ever count the number of balls made per rack when trying for a high run, so yes as Steve assumed I made 5 balls that rack.

SJM, long time no speak I hope you're well mate.

 

[sjm]

SJM, long time no speak I hope you're well mate.

I may take a vacation in England some time this summer. If so, I'll try to get in touch with you in advance.

 

[TheOne]

I may take a vacation in England some time this summer. If so, I'll try to get in touch with you in advance.

Wicked, just let me know in advance so I can time my vacation to coincide! :grin: Just kidding mate, in London now so no worries, hoping to play straight pool again this year so might have to borrow some of that knowledge of yours again!

It will be a cheap vacation that's for sure, under $1.40 for pound today!