TAP Rules Question

MikeM

Pool Lover
Silver Member
Breaker makes three stripes on the break.

On the first shot after break he misses his shot on the 15 but makes the 8 in the side pocket.

For scoring purposes he gets the loss and the opponent the win, but how do you score the balls left on table? There are 4 stripes and 7 solids but who gets what marked on the score card?

MM
 
I believe u would score that as the player who knock the 8 ball in would get the 7 balls marked in LOT colunm and their oppnent would get credit for the 4 solids. Also the player who knocked in the 8 ball would get a mark in the E-8 box.

Biz
 
It seems to me that what he called on his first shot is the suit for which he gets credit.

E.g., if he called a stripe as his first shot and missed it, then he gets 3 balls for the loss.

Good question...not sure it's come up in all the years I've played league.

Did this really happen and how did it get scored?

Jeff Livingston
 
Either way how much difference is it gonna make?
Really? Not much...


Kind of ironic though... Sounds very similar to the "8 ball league scoring question" thread.
 
FLICKit said:
Either way how much difference is it gonna make?
Really? Not much...


Kind of ironic though... Sounds very similar to the "8 ball league scoring question" thread.

Well I agree this is rare and really doesn't matter, but if you read the rulebook or are a Tap player the fact that you can't answer the question is a bit of a problem. Proper score keeping is important to handicaps. All those balls would be marked as "LOT", but what players gets what amount? Thats a interesting question.
 
The person who won the GAME always gets the LOWEST number of balls on the table unless the "stripes" or "solids" has been determined which had NOT been the case in this scenario. If I break and make a solid and then call a solid on my next shot and make one, then miss, and my opponent misses his stripe and makes the 8...at that point the "stripes" and "solids" would count for each player as intended..myself for solids and the opponent stripes.

This also applies to making the 8 on the break. If 14 balls remain each player would have 7 LOT. If the player making the 8 also makes 2 solids, he would only have 5 LOT and the opponent would have 7 LOT...etc
 
Just a question:

If you make an 8 on the break, then why do balls left on table even matter? In this case, it doesn't impact the scoring...

I understand that in other cases when playing games, sometimes balls left on table can show some little information, but overall not much.
 
str8poolbanger said:
The person who won the GAME always gets the LOWEST number of balls on the table unless the "stripes" or "solids" has been determined
I'm just curious where you found this?
str8poolbanger said:
If I break and make a solid and then call a solid on my next shot and make one
Never happened here

stripling said:
This also applies to making the 8 on the break. If 14 balls remain each player would have 7 LOT. If the player making the 8 also makes 2 solids, he would only have 5 LOT and the opponent would have 7 LOT...etc

Good point never saw this before, here is the Taps rule on the 8 on break..

"If the breaking player makes the (8) on the break, the remaining balls left on the table are

added to both players (LOT) column with the breaking player credited with the lower count of

stripes or solids and the opponent or loser with the higher count."

I don't disagree with you by any means, more so curious of where you got your answers
 
SoundWaves said:
... here is the Taps rule on the 8 on break..

"If the breaking player makes the (8) on the break, the remaining balls left on the table are

added to both players (LOT) column with the breaking player credited with the lower count of

stripes or solids and the opponent or loser with the higher count."
Repeating the question: If a player wins by making the 8 on the break, what difference does the balls left on table make?

Just curious is there any logical rationale... Wouldn't adding those balls left on table, essentially screw up the LOT stats? Statistically speaking, of course.
 
FLICKit said:
Repeating the question: If a player wins by making the 8 on the break, what difference does the balls left on table make?

Just curious is there any logical rationale... Wouldn't adding those balls left on table, essentially screw up the LOT stats? Statistically speaking, of course.

I agreed with you earlier, I think there is no point in either of these scores. But as a score keeper both of these scenarios would give you a hard time. They really should add an E8 and 8oB column to the score sheet.
 
I am a former TAP OP. I may have used the wrong wording in stating the the winning player always has less balls on the table.

Scene: I break and dont make anything, you run out 6 balls, make your 7th and also make the 8 on the SAME shot you would lose that game. And I would have 7 LOT.

The reason for marking all balls LOT is because its part of the algorithm that was created by Lloyd in the TAP HC System. Something no OP has ever seen or knows about. We just know there are over 80 algorithms that go into it.
 
Thanks for the replies...

chefjeff said:
It seems to me that what he called on his first shot is the suit for which he gets credit.

E.g., if he called a stripe as his first shot and missed it, then he gets 3 balls for the loss.

Good question...not sure it's come up in all the years I've played league.

Did this really happen and how did it get scored?

Jeff Livingston

I thought this thread had just died away. Yes it happened and no not to me. After much discussion we scored 7 LOT for the winner of the game and 4 LOT for my teammate who made the early 8. Reasoning was balls LOT are a benefit to your handicap (keeping it down) and he should be even further punished for his bad shot. This was a 6 vs. 7 match.

You're right, it doesn't matter much in the long run but it sure stumped us at the time.

Thanks again for the discussion.

MM
 
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