Odds are exactly the same first or last.
I'm still laughing at myself over this one....in my enthusiasm to show off my backgammonP.,
I'm not understanding how 14 byes are actually 28. Do you get two points for winning?
I'm seeing this as:
18 players means 18 possibilities: 14 are byes and 4 are non-byes. The four non-byes represent one match between 2 players in the upper half of the 32 player draw, and one match between 2 players in the lower half of the 32 player draw (16 matches in round 1). The remaining 14 player get byes.
Looks like straight math: 14 to 4 are the odds that any of the 18 draws a bye vs drawing a non-bye. 14:4 is the same as 7:2. So if you were to make a bet on getting a bye, you'd have to lay at least 7:2 for someone to consider it a good bet, or take 7:2 if you were betting on the non-bye.
No they are not. They could be if the ratio of byes to players remains the same, but every time a player is drawn for a bye or a match it reduces.
No they are not. They could be if the ratio of byes to players remains the same, but every time a player is drawn for a bye or a match it reduces.
You could very well end up with all 4 players playing each other happen on the first 4 draws and then it is 100% for the remaining 14 players to get a bye. Or the exact opposite happening at the end.
Oy vey! It's 7:2.Thanks to all who responded and it looks like the consensus is that the odds do not change, they are 7-1 whether he draws first or last.
I knew I could count on you guys, thanks!
I'm still laughing at myself over this one....in my enthusiasm to show off my backgammon
knowledge, I forgot that 14 spots are taken with byes.......
....morons should be more humble...![]()
Oy vey! It's 7:2.
Please don't go back and tell people that the AZB folks set you straight and said it was 7:1.
Freddie <~~~ it's still 7:2