Holy crap, can this be real????
http://www.propool.info/_misc/pool-video.php
it is the first one
20/04/2006 Шутка - девяточные разбои
http://www.propool.info/_misc/pool-video.php
it is the first one
20/04/2006 Шутка - девяточные разбои
Video 9ball break all 9 pocketed on break!!!!!!
- Thread starter PROG8R
- Start date
I suppose it COULD be real, but it isn't. The URL for the download off the page you linked has the file-name as 9-fake-breakshot.mpg. If you watch carefully, what they did is film two clips, one of someone breaking a 9-ball rack, and one of someone hitting a setup shot where all 9 balls are dead in the pockets. They spliced them together so you see the 9-ball break until the frame where the CB hits the one, and then you see the balls flying in from the setup shot clip. Clever trick.
-Andrew
-Andrew
Well, I'll confess now I didn't actually watch the video. The video I described was one I've seen posted here before, and seeing the filename with the word "fake" in it on the video you posted about, I jumped to the conclusion that it was a similar, if not the same, fake. But it could be a better-done fake job, or it could be a different trick than the one I was describing.
-Andrew
-Andrew
Since I can't read russian or whatever the hell language that is, I was unable to find "said" video..
I wouldn't say it's "impossible" to break in 9 balls (becuase you know what happens everytime someone says that word) I'd just say, I would be more then willing to bet the ranch, and let someone rack and break for a year solid and know I'd be the 100,000,000:1 favorite on the odds.. LOL
Most I've ever broke in was 5 balls. I've actually seen that happen a few times over the years. I saw a kid break in 6 once in Santa Barbara.. It wasn't like he was some pro player with a monster break or something, he just broke and they all went in. I think there had to be something wrong with the rack though for that to happen? Either way, he had perfect shape on the the 1st of the last 3 balls, and he was so shaken up by the rack that he ended up missing and losing the game.. LOL
DJ
I wouldn't say it's "impossible" to break in 9 balls (becuase you know what happens everytime someone says that word) I'd just say, I would be more then willing to bet the ranch, and let someone rack and break for a year solid and know I'd be the 100,000,000:1 favorite on the odds.. LOL
Most I've ever broke in was 5 balls. I've actually seen that happen a few times over the years. I saw a kid break in 6 once in Santa Barbara.. It wasn't like he was some pro player with a monster break or something, he just broke and they all went in. I think there had to be something wrong with the rack though for that to happen? Either way, he had perfect shape on the the 1st of the last 3 balls, and he was so shaken up by the rack that he ended up missing and losing the game.. LOL
DJ
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It is the same fake that has been around for a couple of years.
It merges a real break with an 8-ball set up shot. Only 8-balls can be seen going in.
The dead give away is the CB shooting straight through to the bottom rail.
It merges a real break with an 8-ball set up shot. Only 8-balls can be seen going in.
The dead give away is the CB shooting straight through to the bottom rail.
Well...if you had any knowledge of quantum physics like the rest of us, you'd know it was fake.PROG8R said:
nibrobus said:
I'm sure he's still around.. His name is Damien, and it was in Johnny's billiards many years ago. Damien played pretty well back then, I'm sure he's only gotten better with time..
I've actually wanted to make a road trip up there at some point this year and say hello to a couple of those guys I haven't seen in forever. DJ
PlynSets said:I'm sure he's still around.. His name is Damien, and it was in Johnny's billiards many years ago. Damien played pretty well back then, I'm sure he's only gotten better with time..
DJ
I know Damian - he plays pretty good! I don't want to hijack the thread so I sent you a PM.
Just to stay somewhat on topic...the most I ever made was 5 on the break and hung up the nine ball. Didn't have a shot and no good safe and lost the game on a failed attempt on the nine. I didn't break that hard either - the balls just kinda fell in.
Didn't Fast Larry say he made 8 on the break?
Lol
The inertia tensor of a rigid body is defined as the elements of the 3 by 3 matrix
Iij = (r) where the components of the vector r=(x,y,z) are the cartesian coordinates. For a uniform
sphere, ¨(r)=¨ is a constant for r<R and is the density of the ball material. The mass of
the ball is M = V = 43
R3. The kinetic energy of a ball consists of two parts, translational and rotational. The
translational kinetic energy is given by T(Trans)=1/2MV2, where V is the velocity of the
center of mass of the ball. The mass of the ball, M, is the proportionality constant
between the velocity squared and the energy. The rotational kinetic energy about a
principle axis is given by the similar equation T(Rot)=1/2I·2, where · is the angular
velocity, for example in radians per second. Therefore the moment of inertia, I, is the
proportionality constant between the angular velocity squared and the rotational kinetic
energy. The most general equation for the rotational energy of a rigid body is
T(Rot)=1/2·×I×·, in which · is the angular velocity about each axis, I is the 3 by 3 inertia
tensor, and the dot implies the appropriate matrix-vector or vector-vector product. The
quantity L=I· is the rotational angular momentum about the center of mass, and the
simple form for I given above means that for a pool ball the angular momentum is always
aligned with the angular rotation. The rotational energy may then be written as
T(Rot) = 15
( MR2)·×·= 15
( MR2)·2. The freedom of axes choice for a uniform sphere
will often allow the problem at hand to be simplified to only a single rotation axis, in
which case the simple scalar equation may be used.
LOL
Just shoot it.
I knew it had something to do with angles (less than 30 degrees), or linear speed of the CB such that the surface speed of the CB at the contact point will be too fast for friction, on the cloth drag at exactly 32 degrees past Perfect parallel symmetry of the verticle axis when e=mc squared divided by the height of the table rounded to the nearest 1/100000th * the weight of the cue in due boyancey in a iron lung.jsp said:Well...if you had any knowledge of quantum physics like the rest of us, you'd know it was fake.
The inertia tensor of a rigid body is defined as the elements of the 3 by 3 matrix
Iij = (r) where the components of the vector r=(x,y,z) are the cartesian coordinates. For a uniform
sphere, ¨(r)=¨ is a constant for r<R and is the density of the ball material. The mass of
the ball is M = V = 43
R3. The kinetic energy of a ball consists of two parts, translational and rotational. The
translational kinetic energy is given by T(Trans)=1/2MV2, where V is the velocity of the
center of mass of the ball. The mass of the ball, M, is the proportionality constant
between the velocity squared and the energy. The rotational kinetic energy about a
principle axis is given by the similar equation T(Rot)=1/2I·2, where · is the angular
velocity, for example in radians per second. Therefore the moment of inertia, I, is the
proportionality constant between the angular velocity squared and the rotational kinetic
energy. The most general equation for the rotational energy of a rigid body is
T(Rot)=1/2·×I×·, in which · is the angular velocity about each axis, I is the 3 by 3 inertia
tensor, and the dot implies the appropriate matrix-vector or vector-vector product. The
quantity L=I· is the rotational angular momentum about the center of mass, and the
simple form for I given above means that for a pool ball the angular momentum is always
aligned with the angular rotation. The rotational energy may then be written as
T(Rot) = 15
( MR2)·×·= 15
( MR2)·2. The freedom of axes choice for a uniform sphere
will often allow the problem at hand to be simplified to only a single rotation axis, in
which case the simple scalar equation may be used.
LOL
Just shoot it.
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PROG8R said:
Wow, that would be a revolutionary theory if upheld empirically. Colin, can you run some test trials and give us a graph or two on this? That'd be great.
-Andrew
I have seen a video when a guy just casually put two balls together real close, and jump the ball which is like a couple mm away with a full jump cue. I was told the balls were very light and were not real.
One times, someone sent me a video of a person made all nine balls off the break, and asked me if my cue could do the same thing.
To tell you the truth, I really wish I could invent that...
There is a video in Raven cue's site which showed a break like that.
I love these videos, they are so funny. Thank you.
Richard
One times, someone sent me a video of a person made all nine balls off the break, and asked me if my cue could do the same thing.
To tell you the truth, I really wish I could invent that...There is a video in Raven cue's site which showed a break like that.
I love these videos, they are so funny.
Thank you.Richard
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