This post may be a little long, so if you'd like to just cut to the chase, you can just skip to the bold sentences at the end...
I figured out something interesting about tip placement on the texbook rail break, and since I rarely contribute any actual pool knowledge around here, I figured I'd share.
I don't mean to nit-pick what any instructor or pro has said, and assuming I'm right about this, it still doesn't take away from them at all, but I'm just posting this for whatever it's worth.
Anyway, that said...
I have read here and there that the standard 9-ball break should use approximately 1/2 tip of top spin.
Basically, the set up is where the cue ball is placed about 2-4 inches from the side rail and close to the head string. The breaker's bridge hand is placed on the rail. The 1-ball is aimed at for a full hit. If a full hit is made and the rack is tight, the cue ball should rebound back up table towards the shooter, or better yet, directly up the long string towards the center of the table.
Since the cue ball is traveling up table, at a speed that is too fast to naturally stop at center table, there needs to be a very small amount of top spin on the cue ball to get it to "die" at the center of the table.
This made sense to me, and I've probably relayed this information to a few people over time. You can see when a great power break is executed, that the cue ball does just as described above. The problem is that, personally, when I execute this properly, it does not feel like a 1/2 tip of top spin that I used. Rather, it feels like center ball.
Here is a video of Ralf Souquet demonstrating a power break:
http://youtube.com/watch?v=obUceCHVgMU
Watch the cue ball action and you can see, it bounces up table and then abruptly stops. By the time the cue ball is airborne there is undoubtedly top spin on the ball, which creates the braking action after the cue ball returns to the table.
Interestingly, Ralf says to aim a half tip below center, and it looks like that's what he used. This is what got me thinking about what's going on. If the breaker does not strike the cue ball above center, where does that top spin come from?
It is well-known that the cue ball will always be at least slightly airborne on a break, due to the fact that it's impossible to use a level cue. That's why the cue ball always bounces up at least a little bit when it hits the 1-ball on a power break. Since the cue ball is slightly above the 1-ball at impact, collision-induced spin on the cue ball is created. That is, the friction between the cue ball and 1-ball induces top spin on the cue ball. So no matter what spin is used, the cue ball will have a little bit more spin in the forward direction after hitting the 1-ball.
Well, that's it. I think it's really obvious in retrospect, but I hadn't heard that mentioned before, so I thought it was worth posting. I just wanted to share my thoughts in case anyone else finds this interesting, or has anything else to add.
I figured out something interesting about tip placement on the texbook rail break, and since I rarely contribute any actual pool knowledge around here, I figured I'd share.

I don't mean to nit-pick what any instructor or pro has said, and assuming I'm right about this, it still doesn't take away from them at all, but I'm just posting this for whatever it's worth.
Anyway, that said...
I have read here and there that the standard 9-ball break should use approximately 1/2 tip of top spin.
Basically, the set up is where the cue ball is placed about 2-4 inches from the side rail and close to the head string. The breaker's bridge hand is placed on the rail. The 1-ball is aimed at for a full hit. If a full hit is made and the rack is tight, the cue ball should rebound back up table towards the shooter, or better yet, directly up the long string towards the center of the table.
Since the cue ball is traveling up table, at a speed that is too fast to naturally stop at center table, there needs to be a very small amount of top spin on the cue ball to get it to "die" at the center of the table.
This made sense to me, and I've probably relayed this information to a few people over time. You can see when a great power break is executed, that the cue ball does just as described above. The problem is that, personally, when I execute this properly, it does not feel like a 1/2 tip of top spin that I used. Rather, it feels like center ball.
Here is a video of Ralf Souquet demonstrating a power break:
http://youtube.com/watch?v=obUceCHVgMU
Watch the cue ball action and you can see, it bounces up table and then abruptly stops. By the time the cue ball is airborne there is undoubtedly top spin on the ball, which creates the braking action after the cue ball returns to the table.
Interestingly, Ralf says to aim a half tip below center, and it looks like that's what he used. This is what got me thinking about what's going on. If the breaker does not strike the cue ball above center, where does that top spin come from?
It is well-known that the cue ball will always be at least slightly airborne on a break, due to the fact that it's impossible to use a level cue. That's why the cue ball always bounces up at least a little bit when it hits the 1-ball on a power break. Since the cue ball is slightly above the 1-ball at impact, collision-induced spin on the cue ball is created. That is, the friction between the cue ball and 1-ball induces top spin on the cue ball. So no matter what spin is used, the cue ball will have a little bit more spin in the forward direction after hitting the 1-ball.
Well, that's it. I think it's really obvious in retrospect, but I hadn't heard that mentioned before, so I thought it was worth posting. I just wanted to share my thoughts in case anyone else finds this interesting, or has anything else to add.