10-Ball pots in weekly tournaments? physical tickets or electronic?

mikepage

mikepage

AzB Silver Member
Silver Member
It's getting pretty common to have random draws to select a player to break and run a 10-ball rack.

Usually players buy tickets for a buck and maybe have one included with entry fee.

Chosen player must make a ball on the break and then pocket at least one called ball.

If pot is at $N, then balls in are worth $N/10 and player may walk away at any time after making called balls but before missing.

A miss loses everything

My question is,

Does everybody sell physical tickets and pick one out of a jar?

Or does anybody do this electronically. And if the latter, any recommendation for a program/app/website?
 
One can build a random name generator in Excel pretty easily. A google search of how to do it would probably be all it takes. I've made them before, but it's been awhile.
 
mikepage said:
Yes, but I mean something like this

http://wheeldecide.com/
Click to expand...
All of the break pots I've seen around here are with paper tickets.

If you have numbers on tickets (or associated with names), Google has a random number generator that will generate random numbers in a range, such as from 173 to 294. Just search on "random number generator".

Random.org offers a similar on-line service and an app. They claim to use atmospheric noise to generate the numbers.

(Off on a tangent: the services probably use random binary bits to select 1 of N choices. It is not possible to do this without bias unless N is a power of 2.)
 
Bob Jewett said:
All of the break pots I've seen around here are with paper tickets.

If you have numbers on tickets (or associated with names), Google has a random number generator that will generate random numbers in a range, such as from 173 to 294. Just search on "random number generator".

Random.org offers a similar on-line service and an app. They claim to use atmospheric noise to generate the numbers.

(Off on a tangent: the services probably use random binary bits to select 1 of N choices. It is not possible to do this without bias unless N is a power of 2.)
Click to expand...

Thanks Bob --

Care to comment on which of the following is more likely?

(a) The random binary bits problem makes a material difference
(b) Max Eberle has a fundamentally correct world view.
 
mikepage said:
It's getting pretty common to have random draws to select a player to break and run a 10-ball rack.

Usually players buy tickets for a buck and maybe have one included with entry fee.

Chosen player must make a ball on the break and then pocket at least one called ball.

If pot is at $N, then balls in are worth $N/10 and player may walk away at any time after making called balls but before missing.

A miss loses everything

My question is,

Does everybody sell physical tickets and pick one out of a jar?

Or does anybody do this electronically. And if the latter, any recommendation for a program/app/website?
Click to expand...

That's interesting!

Imagine a pool hall with a camera set up and have some big names there.

They sell tickets and they can be purchased at the pool hall OR online. The number gets picked and the winner decides who they want to play the rack! Money won is split! Say 45/45/10! Player/winner/house!

In my head that seems VERY doable!

Eli

P.S. maybe 1 way to get some enthusiasm back in the sport!
 
Wow, as I'm thinking about this, it could end up being something!

Imagine having a night or 2 or 3 even! You can by your tickets anytime up until the cut off time. You have to choose your player within 10 minutes! The player will play the rack out and people and players can make a nice little bankroll!

I don't know why I can see myself throwing 20 bucks a night at this!of you have 100 people do the same thing, you're looking 2k! 900/900/200 payout if rack is completely run!

Eli
 
mikepage said:
... Care to comment on which of the following is more likely?

(a) The random binary bits problem makes a material difference
(b) Max Eberle has a fundamentally correct world view.
Click to expand...
(a) is more likely by at least several orders of magnitude.

CropperCapture[3].png
 
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