7 and the Last two

If a player is getting “7-Ball & the last two” spot in 9-Ball, and only the 6, 7 and 9 remain, if the player with the spot makes the 6 does he win?

No, the last 2 means the last 2 balls that are on the table. The 9, and the ball before the 9. And, then your money balls would be the 7 ball, and the 9 ball. So, in this case, making the 6 ball would not be a win, because the 6 ball is one of the last 3 balls on the table.
 
Last edited:
"Last 2" is one of the weakest spots in 9-ball. It means you win if you make one of the "last 2" balls on the table - regardless of what those 2 balls are (obviously one will be the 9). Say that the 6-7-9 are on the table. If make a 6-7 combo - there would still be 2 balls left on the table, so you didn't make one of the "last 2" - you made one of the last 3. The game continues. At this point, the "last 2" on the table would be the 7 and the 9. So if you make one of those, you win. But the 7 is wild, so the spots converge and you win making the 7 under either spot. In any case, making the 6 is not a win under this fact pattern.

7 and the last 2 is an interesting spot to me. I think you could game this as the spotter by putting the 8 on the wing and hoping it to goes in on the break some times. If the 7-8 are going to be racked at the front, they will almost always be left on the table. The wild 7 makes the weight just a little more "valuable." You could use this to try to up the bet and offer 7 and the last 3. Matching up can be fun.

-td

Well the "Last 2" is not one of the weakest spots in 9-ball. It is in fact one of the best spots depending on the players run-out ability and understanding of safety play. The "Last 2" is in play every game the entire game, and pressure to get all the way out never ends until the final
ball is made.
 
Have any questions, read the attached. If you have questions afterward, then read the attached a 2nd time….Nuf Ced!
 

Attachments

  • IMG_2954.jpeg
    IMG_2954.jpeg
    137.9 KB · Views: 9
Back
Top