7 and the Last two
- Thread starter JohnDurr
- Start date
If the spot is the 7 AND the last 2 the answer is YES
Thomas Martin
New member
No because the 6 ball would only be among the last 3 balls.
"Last 2" is one of the weakest spots in 9-ball. It means you win if you make one of the "last 2" balls on the table - regardless of what those 2 balls are (obviously one will be the 9). Say that the 6-7-9 are on the table. If make a 6-7 combo - there would still be 2 balls left on the table, so you didn't make one of the "last 2" - you made one of the last 3. The game continues. At this point, the "last 2" on the table would be the 7 and the 9. So if you make one of those, you win. But the 7 is wild, so the spots converge and you win making the 7 under either spot. In any case, making the 6 is not a win under this fact pattern.
7 and the last 2 is an interesting spot to me. I think you could game this as the spotter by putting the 8 on the wing and hoping it to goes in on the break some times. If the 7-8 are going to be racked at the front, they will almost always be left on the table. The wild 7 makes the weight just a little more "valuable." You could use this to try to up the bet and offer 7 and the last 3. Matching up can be fun.
-td
7 and the last 2 is an interesting spot to me. I think you could game this as the spotter by putting the 8 on the wing and hoping it to goes in on the break some times. If the 7-8 are going to be racked at the front, they will almost always be left on the table. The wild 7 makes the weight just a little more "valuable." You could use this to try to up the bet and offer 7 and the last 3. Matching up can be fun.
-td
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i think this is correct
the spot is the weaker player wins by making the 7 or the 9
and also wins by making either of the last 2 balls on the table(lower number first)
InsertCleverNameHere
Well-known member
In this case the 7 is also included in the last 2 so it has to be made(or the 9) to win.
100000% no!
Or put another way, the spot would have to be 7 or last three.
No - last 2 is last 2 on the table regardless, Six ball here is one of the last 3 on the table
No. These are two different spots. If the spottee makes the 7 he wins, the last two don't come into play until only two balls are left, any ball and the 9b. So in this scenario/spot the spottee wins by A.Make the 7 anytime or B. Legally pocket one of the two remaining balls on the table. Its a pretty big spot depending on the speed of the player getting the weight.
You're assuming everyone reads every post. Good luck with that.I've always wondered why when a question has been answered do people feel the need to keep answering the question. Hopefully 20 more people will answer
They must not read any posts. Its not just on here, there will be thousands of the same answers.
If I gotta give up that much weight, he's never going to see the 6!! Or the last 2.
Damn. Now I'm so confused!!
Hey wait!! Don't I get a turn??I've always wondered why when a question has been answered do people feel the need to keep answering the question. Hopefully 20 more people will answer
When my grandson first started playing, I would spot him two balls after the break when he wanted to play 8 ball. It took him awhile to realize the spot worked in my favor bcuz he'd always pick the cluster or tied up ball, doing my work for me.
He doesn't take the spot anymore.
OK, you get a turn cause you asked nicely