Bar pool ball in hand

alstl

AzB Silver Member
Silver Member
That doesn’t make it fair.

The key word was "in a bar" - quarters required to get the balls back out of the table. One the 8 ball goes in it is either a win or a loss because without the 8 ball you can't play 8 ball.
 

Swighey

AzB Silver Member
Silver Member
The key word was "in a bar" - quarters required to get the balls back out of the table. One the 8 ball goes in it is either a win or a loss because without the 8 ball you can't play 8 ball.

Yes, so a new rule has to come into play. The standard, non coin-op rule is that there is a choice of re-racking or re-spotting the 8. This rule is in place because of the neutrality of the break shot and the value of striking the ball hard without calling a ball and pocket. If the 8 goes down it is regarded as unlucky and the breaker is not penalised as he or or she normally would be for an early 8. On a coin-op it appears that we can do one of two things:

1) make it a loss because that’s what happens in every other situation where the 8 goes in early,
2) make it a win because we don’t want to see the breaker penalised.

Option 1 maybe has more logic to it but a much better solution is to restart the game with same players. The breaker holds the table and the other player pays for the game. There is then some small reward (half a game fee) for the breaker and the other player doesn’t lose the option of ether playing or being run out on.

The nature of 8 ball is that you win by sinking the 8 on a legal shot after and only after all the balls of your group have gone down. This is the best solution. How it’s actuslly done is another issue altogether. I’ve seen breaker loses, but seen breaker wins far more often (yes almost universally). But there are bars, where the owner/manager is a pool guy where the third option is employed ( or even better, the bar pays for the balls to be released in this situation).
 
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