Consider me an Idiot ............

Its not considered or called a foul. You can push out after the break and make a money ball, but it will spot, just like the 9 ball would. Sometimes its advantageous to not leave a money ball near a pocket if theres a low ball combination to be had. You can however make the money ball during the course of the game on a legal shot, ie lowest ball hit first, and it stays down.
Chuck
 
In the old two- foul ball in hand rules....the FIRST foul was usually a PUSH.
...the penalty for that push was that your opponent had the option to shoot or give you
the shot back.

So a push is a foul.....try scratching after your push and see if your opponent
doesn't tell you you're two.

Where the hell is Bob Jewett when I need him.
 
Being uneducated about the terms of gambling does not meen you cant run racks...... it simply meens I do not gamble playing pool and was curious what it ment.
 
Never Say Never

If I'm giving you the "last 4" and the 6/7/8/9 are on the table I can make one of them on a push out and it DOES stay down. Then the next lowest ball on the table becomes a "money ball". Obviously rule books don't cover gambling, but this rule is accepted in the every money game I've ever played (which is in the thousands).

This is the only exception I can think of to the "never" stay down statement you made.;)

The "push out" is a foul, it's just not a "ball in hand" foul on the first shot (playing tournament rules player has option to shoot or pass).

Playing 'Two Shot Shoot Out' (2 Foul) you can push out, and you're on "1 Foul," if you foul again (scratch or otherwise) it's "ball in hand" for your opponent.




Besides what? You said nothing in your first paragraph.

I've already stated that moneyballs never stay down on a foul/pushout.

ONB
 
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If I'm giving you the "last 4" and the 6/7/8/9 are on the table I can make one of them on a push out and it DOES stay down. Then the next lowest ball on the table becomes a "money ball". Obviously rule books don't cover gambling, but this rule is accepted in the every money game I've ever played (which is in the thousands).

This is the only exception I can think of to the "never" stay down statement you made.;)

The "push out" is a foul, it's just not a "ball in hand" foul on the first shot (playing tournament rules player has option to shoot or pass).

Playing 'Two Shot Shoot Out' (2 Foul) you can push out, and you're on "1 Foul," if you foul again (scratch or otherwise) it's "ball in hand" for your opponent.

Not sure what his reply will be but I'm sure it'll end with "Learn to play".
 
I actually think that if you have more than 100 posts on this forum, and you DON'T know just about every gambling spot there is, you should be banned for a month till you learn LOL

I know all those and I play for $10 a few sets once a week max.

Lets play that out for a ban of one month for every 100 posts made. If that were true, and you were banned for a month for every 100 posts you had, I'd never be back :)

I appreciate (most of) this thread. I learned a little. Probly never use it, but I understand the conversation better now.
 
The game of pool is perfect, it's just up to us to uncover that perfection.

We all have to "learn how to play," and the GAME is the teacher. ;) The game of pool is perfect, it's just up to us to uncover that perfection.

Not sure what his reply will be but I'm sure it'll end with "Learn to play".
 
If he claims it's a foul to make any ball on a pushout, then yes. Show me ANY official rules that making a ball on a pushout is a foul and I'll eat my words.

BTW, you said learn to play, not learn to gamble. They're finishing loading that match up to youtube as we speak if YOU want to learn to PLAY....

Jaden

Hey genius, what are you waiting for??? The Sun to be farther from the Earth in the winter???

P.S. Read a book.

ONB
 
You cannot ever, in any 9 ball game, shoot an opponents money ball in on a foul or pushout or whatever you want to call it without it spotting up.

Learn to play.

ONB

Actually if you're giving a player "the last 4" and the 6/7/8/9 are on the table you can shoot the 6, 7, or 8 in on a "roll out" WITHOUT them spotting back up.....if you shoot in the 6 ball, the 5 (or 4) becomes one of the "last 4" money balls.....the 6 ball would stay down.

Besides that it is universally true that "money balls" never stay down on a foul/roll out.

This is just another example of you not posting clearly what you mean. If there are other balls on the table AND the 6,7,8 & 9 and you shoot in the 6, 7, or 8 on a foul shot of course one of the other balls becomes a money ball but only when there are 4 balls left on the table.

The 6, 7, 8 and 9 would only be money balls if they were the last 4 balls on the table in your example. They would never be money balls until they were the last 4 balls on the table so your argument is a joke, much like most of everything you write here.

ONB
 
grumpycat_141210102125.jpg
 
Iam fairly new to the 9 ball scene so just wondering what does it meen when someone says ..." you got the 8 or the 7 or 6 or whatever" ???

Never ever assume. Make sure to pull a pen and a paper and write the following:

1- I get the 7 any way or shape no calling, lucky i win, even on break,
2- I get the 8 any way or shape no calling, lucky i win, even on break, provided you hit the smallest ball on table
3- 9 obvious you win provided you hit the smallest ball on table

write any other rules you two think of!


if you playing 1 pocket write the spot down on table using chalk..


All games, make sure if you flip a coin for the break, to hear what the opponent say and repeat it so he does not flip on you !!
 
it's not "a joke," you're simply wrong.

This isn't accurate, I know it's not "a joke," you're simply wrong.

If the 5/6/7/8/9/ are on the table and you're getting the "last 4" the "money balls are the 6/7/8/9 - if you shoot the 5 and "accidently" (or on purpose) make either the 6/7/8 or 9 you win......this means they are ALL money balls even if there's more than 4 balls on the table.


This is just another example of you not posting clearly what you mean. If there are other balls on the table AND the 6,7,8 & 9 and you shoot in the 6, 7, or 8 on a foul shot of course one of the other balls becomes a money ball but only when there are 4 balls left on the table.

The 6, 7, 8 and 9 would only be money balls if they were the last 4 balls on the table in your example. They would never be money balls until they were the last 4 balls on the table so your argument is a joke, much like most of everything you write here.

ONB
 
This isn't accurate, I know it's not "a joke," you're simply wrong.

If the 5/6/7/8/9/ are on the table and you're getting the "last 4" the "money balls are the 6/7/8/9 - if you shoot the 5 and "accidently" (or on purpose) make either the 6/7/8 or 9 you win......this means they are ALL money balls even if there's more than 4 balls on the table.
The fact you have to explain this is mind boggling. I can see the new guy not knowing, but a supposedly experienced player not knowing is crazy.

You're a patient man CJ.
 
It means this

Iam fairly new to the 9 ball scene so just wondering what does it meen when someone says ..." you got the 8 or the 7 or 6 or whatever" ???

You are probably talking to someone without a job.
And they are trying to steal your money.
Nick :)
 
This isn't accurate, I know it's not "a joke," you're simply wrong.

If the 5/6/7/8/9/ are on the table and you're getting the "last 4" the "money balls are the 6/7/8/9 - if you shoot the 5 and "accidently" (or on purpose) make either the 6/7/8 or 9 you win......this means they are ALL money balls even if there's more than 4 balls on the table.

This explanation distorts the situation.
So, if you're playing even-up 9-ball, you can say ALL balls are the money ball....
....because you can make the 9 whilst shooting any of them?


Just step away from the Zen for Dummies

:)
 
getting "the last 9" you could say all the balls are "money balls," and they are

No, but if you were getting "the last 9" you could say all the balls are "money balls," and they are......even if you made one on the break you would win.


This explanation distorts the situation.
So, if you're playing even-up 9-ball, you can say ALL balls are the money ball....
....because you can make the 9 whilst shooting any of them?


Just step away from the Zen for Dummies

:)
 
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