More Break Cue talk
- Thread starter GoldCrown
- Start date
Thanks Shooter. Pechauer has nice stuff. I should have mentioned I'm trying to keep it under $200.
force equals mass x acceleration
from what i recall when i looked into it
the proponents of the lighter break cues emphasized the acceleration
and the proponents of the heavier break cues emphasized the mass
its been awhile since i researched it
fwiw i bought a jump break more for how well it jumped
(alex brick not made anymore ...R.I.P. ALEX)
good luck frank
p.s. you dont have to break hard in onepocket...........:lmao:
from what i recall when i looked into it
the proponents of the lighter break cues emphasized the acceleration
and the proponents of the heavier break cues emphasized the mass
its been awhile since i researched it
fwiw i bought a jump break more for how well it jumped
(alex brick not made anymore ...R.I.P. ALEX)
good luck frank
p.s. you dont have to break hard in onepocket...........:lmao:
That's the equation.
Force = mass x velocity squared is another way to look at it.
So... since the velocity is multiplied times itself, it is the most significant if one wants a change, an increase in force.
A single unit increase in velocity is more beneficial than a single unit increase in mass.
If an increase of a single unit of mass reduces one's ability to produce an equal amount of velocity then the force will likely be reduced.
It's a touchy equation given the implementation.
My suggestion for anyone that has not already done the experiments to find the ideal mass/weight for them, who is in the market for a break cue, would be to get one that can be adjusted for weight & then do the experimenting.
One ounce too heavy can be disastrous for the intended purpose of power, especially for us older guys (& gals). The same can be true for a cue that is too light but generally one can move a light cue fast enough to make up for it, but not always.
So... it can come down to how one intends to use the cue. Does one want to stroke for power or does one to just let the cue do the work.
If one wants the cue to do the work with an 'easy' stroke then heavy is generally better.
Best Wishes for ALL.
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Thanks....I will check with Scott Lee on this.
You have the right idea.
I have a CueTec Break/Jump (currently at a different location). It works fine. I have cheap 2 piece cues I might use. When the ferrule breaks I can replace it and install a break tip w/pad. Also can buy a CueTec break shaft and use it on an existing CT butt however they run close to $90.
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Thanks ... Think I'll buy/use a dedicated breaker. I have never jumped and most likely won't.
Just for the sake of conversation what does an expensive vs inexpensive break cue do aside from lasting longer. For example Predators do cost. Are they worth it aside from having a quality breaker. Again..it's the archer not the arrow.
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I believe it was Justin from TAR who mentioned in a stream somewhere along the lines that the fastest possible acceleration combined with the highest weight was 21 oz but I could very well be wrong. I prefer to have my playing cue and break cue weight similar or my break +/- .5 Oz
I know there is no substitute for trying and seeing what works best. Someone wrote lighter is better...all kinds of theories I guess. CueTec bullet is looking good and they are durable cues. I might buy a Predator but honestly it is burning money.
I just bought a players jb. For about 100 bucks, its a VERY hard to beat break cue. Dont need the jump joint? Never crack it open...... :thumbup:
19 oz btw
i have an $85 break cue.
i tried a $400 Predator last Saturday.
I saw no difference except the other guy paid $315 more than me for the Predator.
<<<<<<<<Tried $400.00 Predator, Viking, Jacoby Heavy Hitter, OB, and various other break cues, spent $0 on break cue, uses player to break, even when it used to have a soft tip.
Minor nit (it's a major nit, but only if we're picking nits)...
acceleration does not equal velocity squared, and F does not equal mv^2
However, if we look at the energy, then kinetic energy = 1/2 (mv^2)
Since energy is conserved, Nature tends to balance it out. Given a constant energy in, energy out should be about the same.
I normally like to consider things like:
energy loss or energy transfer efficiency (favors heavy cues)
inertia and the ability to get to speed (favors lighter cues?
Breakers breaking style (arm breakers favor heavy vs wrist breakers favor light???)
Freddie
The force equation won't be relevant. The acceleration at contact on most shots are near zero, so the force would be near zero. It would be interesting to find out what the acceleration actually is at the point of contact on the break, but in the end, it's a pretty meaningless metric for the collision.
The Kinetic Energy or the Momentum (and therefore Velocity) on the other hand, needs to be at its "efficient maximum" (I'm sure someone will claim this term years from now.. it's been mine for years) for the break.
The efficient maximum velocity is that max velocity that a breaker can still control the cueball and get the most solid hit. Some breakers will achieve that efficient maximum with a lighter cue while others will with a heavier cue, all depending on the breaker's body and breaking style.
Freddie <~~~ 1988, Letter to the Editor
I don't have much to add but I know a pretty well known cue maker that breaks with something like a 15oz cue but his shooter is probably around the same. I love my McDermott Stinger shaft for jumping but other than that I haven't found a cue that really makes my break any better than normal.