Progressive Pot Idea

B

bobprobst

AzB Silver Member
Silver Member
now I'm sure this has been mentioned before but here it is.

Bar tables always have a queue of people waiting to play so here's the prop.

I put a dollar on the rail. Next player matches the pot (a dollar in this case) and we play the match.

The winner can either take the pot or take the table. That is, if they win, they can take the $2 (in this case) and the loser keeps the table or they can take the table (and no cash) and the next player matches the pot (now $2).

Person in control of the table always racks their own and always takes the break.

So assuming that player A and B put up $1 and player A wins. He can take $2 and leave the table to player B (who can do whatever he wishes with it). Or player A (the winner) can leave the $2 on the rail and keep the table and will then welcome player C to the table. Player C must bet the pot ($2 for a total of $4 in the pot) and then the sequence starts again.

If A wins the second match, he can take the $4 (leaving the table to the loser, player C) or compete with player D who must match the $4.

Etc etc.

So the pot goes rapidly 2, 4, 8, 16, 32, 64, 128, 256, etc

Player 1 just needs to win 4 in a row to turn their $1 into $16. Or 5 gets you $32!

Assuming players of equal strength and you on a winning streak, when do you hand over the table?

That is, when does your wallet equal your ego?
:)
 
What is my bet?

bobprobst said:
now I'm sure this has been mentioned before but here it is.

Bar tables always have a queue of people waiting to play so here's the prop.

I put a dollar on the rail. Next player matches the pot (a dollar in this case) and we play the match.

The winner can either take the pot or take the table. That is, if they win, they can take the $2 (in this case) and the loser keeps the table or they can take the table (and no cash) and the next player matches the pot (now $2).

Person in control of the table always racks their own and always takes the break.

So assuming that player A and B put up $1 and player A wins. He can take $2 and leave the table to player B (who can do whatever he wishes with it). Or player A (the winner) can leave the $2 on the rail and keep the table and will then welcome player C to the table. Player C must bet the pot ($2 for a total of $4 in the pot) and then the sequence starts again.

If A wins the second match, he can take the $4 (leaving the table to the loser, player C) or compete with player D who must match the $4.

Etc etc.

So the pot goes rapidly 2, 4, 8, 16, 32, 64, 128, 256, etc

Player 1 just needs to win 4 in a row to turn their $1 into $16. Or 5 gets you $32!

Assuming players of equal strength and you on a winning streak, when do you hand over the table?

That is, when does your wallet equal your ego?
:)
Click to expand...

If I walk up and pay $4 and win, does someone else pay $8 to play me for $16?
 
That's the progression. And let's assume you have an infinite number of opponents as skilled as you in line willing to pay any amount of money into the pot. When do you take the pot? vs taking another round of bets?
 
An interesting proposition with a fair number of factors affecting play and a player's thinking. I like it!
 
Excellent concept, sir. I'll certainly suggest your idea at our next practice night. :)

One question, please: what happens if a player wins up to a certain level, decides to carry on, but nobody else on the waiting list cares to challenge him for so much money?

Kind regards,
RC.
 
Rubik's Cube said:
Excellent concept, sir. I'll certainly suggest your idea at our next practice night. :)

One question, please: what happens if a player wins up to a certain level, decides to carry on, but nobody else on the waiting list cares to challenge him for so much money?

Kind regards,
RC.
Click to expand...

Would think it would be his money & table if nobody puts the money up for challenge. Put a fresh dollar on the table, then take on the next player that steps up.

This is an interesting concept that I'll bring up with my shooting buddies.
 
(((Satori))) said:
But just one more game and both you and your wife could each have a cool mil.:)
Click to expand...

Sure, but the incoming player has to match the pot every time to get there :D

BTW I really like this idea, so thank you to the opening poster for coming up with it!!
 
1pocket said:
Sure, but the incoming player has to match the pot every time to get there :D

BTW I really like this idea, so thank you to the opening poster for coming up with it!!
Click to expand...

It is good and the solution for the winner to pocket pot when incoming won't ante up (is straight up MOP) is good too. I'd add that since the winner was the winner, he should obviously be the lead off man in the next round.

You could win a lot starting with a little at that game. Opposite also applies.
 
Nobody can figure out if a scratch on the break is an automatic loss on bar tables, how does anyone think that this will be understood in a bar on a barbox?? :confused: I love the idea though. :wink:
 
1pocket said:
Sure, but the incoming player has to match the pot every time to get there :D

BTW I really like this idea, so thank you to the opening poster for coming up with it!!
Click to expand...

We were answering post 3 where the thread starter asked how many games we'd play assuming an infinite amount of opponents willing to ante up any amount.
 
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