Consider 2 cue balls rolling down table at 1 foot per second. The first CB (left) has natural roll while the second CB (right) has side spin equal to its rolling velocity::
The point of contact with the table of each CB moved down table at 1 foot per second (equal velocity).
The equator on the first CB is rotating at 1 foot per second. and the pat of rotation is the equator of the rolling ball. The equator is moving at 1 foot per second over the cloth.
The path of rotation of the second CB is displaced from the equator (due to the side spin) but the part of rotation remains 1 foot per second over the cloth. The equator in this case is now rolling at 1.414 feet per second. Thus the second CB has more angular momentum and thus more energy even while traveling at the same velocity (1 foot per second).
The friction of the cloth on the table saps energy from the CBs at equal point-of-contact speeds equally. But the second CB has more energy and thus rolls farther.
The point of contact with the table of each CB moved down table at 1 foot per second (equal velocity).
The equator on the first CB is rotating at 1 foot per second. and the pat of rotation is the equator of the rolling ball. The equator is moving at 1 foot per second over the cloth.
The path of rotation of the second CB is displaced from the equator (due to the side spin) but the part of rotation remains 1 foot per second over the cloth. The equator in this case is now rolling at 1.414 feet per second. Thus the second CB has more angular momentum and thus more energy even while traveling at the same velocity (1 foot per second).
The friction of the cloth on the table saps energy from the CBs at equal point-of-contact speeds equally. But the second CB has more energy and thus rolls farther.