Keep in mind that SVB had a buy-back option and he did use it after losing to Alex. So that changes the overall probability considerably.
Things get a little complicated factoring the buy-back and the redraw, but let's keep it simple and assume that if you do lose and buy-back, you still have to win against the same number of people. So if x is the probability Shane wins against a given Filipino and n is the number of Filipinos he has to face, then the overall probability P he will get through all n Filipinos (using or not using the buy-back option) is...
P = x^n + n*(1-x)*x^n
The first term is the chance Shane makes it through without using the buy-back (goes undefeated) and the second term is the chance he makes it through while using the buy-back (one loss).
If n=5 and plugging a few probabilities for x gives...
x = 0.5 -> P = 10.9%
x = 0.6 -> P = 23.3%
x = 0.7 -> P = 42.0%
x = 0.8 -> P = 65.5%
x = 0.9 -> P = 88.6%
So for the case that Shane is 80% likely to beat a Filipino (x = 0.8), the buy-back options he had available essentially doubles his chances that he'll make it through all 5 Filipinos.