So lemme just clear it up in my head.
The procedure for a 2 way tie is: Look at all the matches the tied teams ever played.
Add up all the points A scored vs. B
Add up all the points B scored vs. A
Whichever team has more points, wins the tiebreaker.
If the points add up to the same number, whoever won their last match wins the tiebreaker.
So a three way tie is handled by doing this procedure between 2 of the tied teams.
They aren't randomly picked but they might as well be...
it's the 2 teams that faced each other earliest in the season.
This determines a winner between 2 of the teams.
Then they repeat the procedure with the winner, and the 3rd team.
I can sort of see their reasoning but I also don't agree with it.
On paper, B is the best team.
But when C played against B, C managed to fight them to a tie.
So they're considered equals. The 'winner' is decided basically by a coin flip.
So of these 2 powerhouse teams, C comes out on top.
The one time C ever matches up with A, the winner was A.
So A is chosen as the "best" team.
This is kind of a common pool fallacy. Bob beats Timmy. Timmy beats Joe.
So on paper, Bob beats Joe and Bob is the best player.
But in practice, Bob might lose to Joe and maybe he doesn't beat Timmy
if you lengthen the race.
The same false reasoning was applied to this tie. C beats B. A beats C. So A is the best.
Even if they really aren't. I agree looking at overall win/loss (like a round robin) would be a
more fair way to break the tie.
An even better way would be to just let the teams match up on a pool table
instead of on paper.
The procedure for a 2 way tie is: Look at all the matches the tied teams ever played.
Add up all the points A scored vs. B
Add up all the points B scored vs. A
Whichever team has more points, wins the tiebreaker.
If the points add up to the same number, whoever won their last match wins the tiebreaker.
So a three way tie is handled by doing this procedure between 2 of the tied teams.
They aren't randomly picked but they might as well be...
it's the 2 teams that faced each other earliest in the season.
This determines a winner between 2 of the teams.
Then they repeat the procedure with the winner, and the 3rd team.
I can sort of see their reasoning but I also don't agree with it.
On paper, B is the best team.
But when C played against B, C managed to fight them to a tie.
So they're considered equals. The 'winner' is decided basically by a coin flip.
So of these 2 powerhouse teams, C comes out on top.
The one time C ever matches up with A, the winner was A.
So A is chosen as the "best" team.
This is kind of a common pool fallacy. Bob beats Timmy. Timmy beats Joe.
So on paper, Bob beats Joe and Bob is the best player.
But in practice, Bob might lose to Joe and maybe he doesn't beat Timmy
if you lengthen the race.
The same false reasoning was applied to this tie. C beats B. A beats C. So A is the best.
Even if they really aren't. I agree looking at overall win/loss (like a round robin) would be a
more fair way to break the tie.
An even better way would be to just let the teams match up on a pool table
instead of on paper.