I ain't no 1p player, but the calculus of this seems hard to refute: A move that goes from ZERO balls on your side (effectively as it is now) to having TWO balls on your side (and in not really great bank territory for the other side) has to be a pretty strong one.
So feather the 8 enough to rearrange the 8 and 9 well, and bring the CB down to his side, on the rail hopefully lower than the second diamond, and you've done well. Neither the 1 or the 3 seem safe to shoot at with you needing only 2 balls--which could easily come into play.
In fact at that point his next shot would probably be to bank the 8 or 9 up table.
Leaving the 8-9 as they are seems to actually give more play to HIM than to you.
EDIT: Just looked again and I see that the CB position makes handling it well difficult. Might have to hit the rail first before hitting the 8, in order to break them and head to his lower side rail.
So feather the 8 enough to rearrange the 8 and 9 well, and bring the CB down to his side, on the rail hopefully lower than the second diamond, and you've done well. Neither the 1 or the 3 seem safe to shoot at with you needing only 2 balls--which could easily come into play.
In fact at that point his next shot would probably be to bank the 8 or 9 up table.
Leaving the 8-9 as they are seems to actually give more play to HIM than to you.
EDIT: Just looked again and I see that the CB position makes handling it well difficult. Might have to hit the rail first before hitting the 8, in order to break them and head to his lower side rail.
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