Ball Compression Contact Patch Marks Showing How Much Balls Compress and Flatten During Impact

I'm pretty sure the one ball was always in front. That makes it more puzzling, since contact on the six would have been like a combination.

I was hitting the breaks mostly from the center with a square hit, and the racks were always tight (with my trained table), so there were large forces throughout the rack.
 
They have stickers that you put on the face of a golf club to see where on the face the ball impacts. It's a kind of a swing correction tool. Maybe put something in front of the rack, leaning against the head ball, and see if the impact patch is captured on that.
I wouldn't think it would be so uniform unless the break speed is also that uniform.

When I've used pieces of tissue paper between the balls to simulate gaps in different parts of the rack, the contact patch was clear in the part of the tissue that got smashed. It had a similar size and shape as the white marks on the balls.
 
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It's pretty easy to see that there has to be a contact patch of some size. Imagine two balls coming at each other at the same speed. There's a plane between them that neither ball will cross. Because the contact is not instantaneous, there must be a round flat spot (or nearly flat) of the contact between the balls.

If you know the size of the contact patch between the balls, you can fairly easily calculate the contact time if you know the speeds of the balls. Or you can measure the contact time directly, as Dr. Wayland Marlow showed in his book on billiard physics. That time is about 100 to 200 microseconds depending on the speed of the shot.
 
If you know the duration of contact between the balls, you can fairly easily calculate the contact time if you know the speeds of the balls. Or you can measure the contact time directly, as Dr. Wayland Marlow showed in his book on billiard physics. That time is about 100 to 200 microseconds depending on the speed of the shot.

For those interested, there is more data and info on this topic here:

 
I could see a firm cut shot creating an oval contact patch instead, just like tennis balls glancing off the court (as the electronic line-calling cameras show on TV).
Hmm. If you look closely at the oval tennis ball marks you’ll see that they are all skids, usually accompanied by some yellow fuzz, amount depending on the surface. It is extremely difficult for us mere mortals to get enough topspin on a ball, especially on serves or overheads, to have the ball rotating at impact speeds.

With tennis balls you are also looking at the impact pattern from an obloid (that compresses perpendicularly to the direction of motion) and a plane ( might get a small amount of compression on a soft court, certainly some on grass) vs two spherical balls that would compress similarly. I have trouble visualizing how you can have long enough contact time on the balls to get an oval unless there is a lot of English on the impacting ball or the impacted ball is frozen to a rail.
 
I've always thought these marks were from playing with dirty balls and/or cloth.
The only time I've noticed them is on public room sets and when I'm lazy at home and haven't cleaned up for a few hours.
 
The balls not only compress they also rub against each other. And that movement can be vertical and horizontal.
 
It's pretty easy to see that there has to be a contact patch of some size. Imagine two balls coming at each other at the same speed. There's a plane between them that neither ball will cross. Because the contact is not instantaneous, there must be a round flat spot (or nearly flat) of the contact between the balls.

If you know the size of the contact patch between the balls, you can fairly easily calculate the contact time if you know the speeds of the balls. Or you can measure the contact time directly, as Dr. Wayland Marlow showed in his book on billiard physics. That time is about 100 to 200 microseconds depending on the speed of the shot.
If the contact time is linearly proportional to the speed, yes, but this whole discussion looks and acts non linear, hence the videos and the usual transition from theory to engineering. I was getting about 250 microseconds from the videos Dr Dave posted. No good way to relate that to speed with only one data point.
 
Boy this went down a rabbit hole. Done went got all dweeb-ish on me. You fellers r 2 edgeecated fur me. Linear micro what?? ;)
 
It's pretty easy to see that there has to be a contact patch of some size. Imagine two balls coming at each other at the same speed. There's a plane between them that neither ball will cross. Because the contact is not instantaneous, there must be a round flat spot (or nearly flat) of the contact between the balls.
In case anybody wonders...

A ~1/8" contact patch (as shown), flattens less than 1/1000 inch (on each ball).

pj
chgo
 
At what speed? Or is the size of the patch representing the speed? I would think that is the case.
 
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