Now to the OP situation in CSI play...
Player A breaks and doesn't make anything but thinks he does. Proceeds to shoot in 2 balls at which point the opponent tells him he didn't make anything on the break. What is the call?
In CSI play, this specific situation is not addressed. For better or worse, the act of shooting out of turn is not specifically defined or addressed in CSI rules.
The closest common sense fall back would be CSI Rule 2-3, 8-Ball Break Requirement, last sentence:
If you do not legally pocket a ball or you commit a foul, your inning ends.
combined with and CSI Rule 1-23-2:
Any foul not called before the next stroke is taken is considered to have not occurred.
If I were a TD, or a head ref adivsing a TD asking for an opinion, I would combine those two principles but would lend the most weight to 1-23-2. I would advise that the game continue with the player who broke continuing to shoot. Even if you consider the initial shot out of turn to be a foul, once it was not called after the first shot it was not enforceable after that point. The net effect, and a defensible position under CSI Rule 1-42-2 first sentence first clause, is that the non-breaking player gave up his turn by not approaching the table or making any effort to stop the breaker.
If a TD simply decided to re-rack, I would have absolutely no problem with that either. I think it would be a defensible position in the spirit of CSI Rule 2-6-1 and 2-6-3.
Of course, none of this is official. Been awhile since I've been writing the book. Just .02 from an experienced rule writer.
Buddy