how many 2.25 pool balls fit on a 9 ft 50 x 100 billiard table?

[OTLB]

It depends on the shelf debth. :groucho:

billiard tables don't have a shelf but I see why you say it

 

[OTLB]

It depends on the shelf debth. :groucho:

balls are 2.25 using std SS cushions, surface is 50 x 100

 

[mechanic/player]

Continued R+D has proven that Cuephoric has got to be within 10 balls of the number at 978, no?

 

[OTLB]

fun doing R=D isn't it, especially when you get the right result, please try again

maybe a guy with 26 years exp can take a poke

 

[claymont]

1110.6416369891953884227681535583 96x46
3.97608
1257.5199694171143437757791593731 50x100

20.444444444444444444444444444444 46X96
42.666666666666666666666666666667
872.296
840 ROUNDED

22.222222222222222222222222222222 50X100
44.444444444444444444444444444444
987.65432098765432098765432098756
968 ROUNDED

 

[realkingcobra]

fun doing R=D isn't it, especially when you get the right result, please try again

maybe a guy with 26 years exp can take a poke

With deep shelf slates, 1,111, otherwise 1,107

 

[OTLB]

there are no shelves on a billiard table

 

[realkingcobra]

there are no shelves on a billiard table

Same 5,000sq inches divided by 4.5sq inches per ball making it 1,111 balls

 

[brain]

1097

Several ways to do it:

If you start on the long cushion you can fit 44 balls (100/2.25=44.4), the next row up fits in between the balls from the first row (like in the rack - hexagonal close packing), BUT 44 balls cannot fit accross (44.5*2.25=100.125), so you can only fit 43. The distance between rows is 1.94 (sin 60*2.25), and thus 25 rows. 13*44 + 12*43 = 1088.

If you start on the short rail, you can fit 22 balls in the first row but again only 21 in the row above. 51 rows will fit - 26*22 + 25*21 = 1097.

If you pack them in a standard cubic array you'dd have 22*44=968.

Assuming the 50x100 is the true boundary and that balls cannot fit into the jaws.

 

[OTLB]

anyone think he is wrong

 

[MitchAlsup]

I, for one, am sure the hexagonal packing is the optimal technique.

 

[scottp]

i got 968 without stacking

scott

 

[barefoot3zk5]

count

I get 1075 balls per 50 x 100... Yes or No ???

 

[barefoot3zk5]

Rand D on paper

Check my math sir,

 

[n10spool]

1 st plan I got more I beat em with a hammer and I quit counting I got carple tunnel and a maxed out credit card and didnt reach the point of the cusion.

2nd plan I swiched to golf and now my back hurts

 

[OTLB]

there is a winner and would like to see more

 

[barefoot3zk5]

winner ??

If I win somethin , send it to me ... LOL

Sorry glen, math says sq inches of 2.25" ball is 2.25 x 2.25=5.06
not 2.25 + 2.25= 4.5 ... break out magic eraser for math, HaHa

me and Elvis did the cipherin on that...

 

[Ben at Muellers]

If you were allowed to stack them I think you could get 9361.

 

[PoolTable911]

1097

Several ways to do it:

If you start on the long cushion you can fit 44 balls (100/2.25=44.4), the next row up fits in between the balls from the first row (like in the rack - hexagonal close packing), BUT 44 balls cannot fit accross (44.5*2.25=100.125), so you can only fit 43. The distance between rows is 1.94 (sin 60*2.25), and thus 25 rows. 13*44 + 12*43 = 1088.

If you start on the short rail, you can fit 22 balls in the first row but again only 21 in the row above. 51 rows will fit - 26*22 + 25*21 = 1097.

If you pack them in a standard cubic array you'dd have 22*44=968.

Assuming the 50x100 is the true boundary and that balls cannot fit into the jaws.

I going with this guy...Just look at his name

 

[OTLB]

as"YODA" says mmmmmmmmm smart this one is. Game over

BTW Pat one of the snooker tables that I sold to Dave you were asking about was purchased\owned by YODA ( Frank Oz)and I have provenance pics for future sale value. A great story to go with how I got the table for free from him also.