It's not literally true from a physics perspective that the CB will be dead (i.e. have no sidespin) after transferring maximum sidespin to the OB. It's true that the amount of spin gained by the OB is equal to the amount lost by the CB, but the CB can only transfer a small percentage (about 36% max) of its spin even under ideal high-friction conditions. The CB will always retain most of its spin.
However, the idea may serve as a useful reminder to some that you achieve max spin transfer with less than max english. You can transfer up to 36% of the CB spin up until the point where the CB starts slipping against the OB instead of adhering to it. Once you have a slipping contact, you start transferring less. That's why if the CB spins a lot after contact, it probably wasn't max spin transfer (lots of leftover CB spin indicates a sliding contact).
Robert
Robert,
Your statements make a lot of sense although 36% seems like a phenomenal amount of transfer of spin.
What do you think is the maximum percentage of spin transfer is possible on brand new Simonis cloth on pocket billiard tables?