The equal break chances discussion...
I think at the top level, lets say Shane and Wu playing winner break 9 ball with magic rack, where they will hypothetically run a 5 pack every time they come to the table... If that were to happen, I think the system would still balance out. In that case, every inning of a player is worth 5 games. But since they are both running 5 every inning, it balances out. They both had equal opportunities.
Now, lets say it was a race to 10. Wu runs 5, then Shane runs 5, then Wu runs 5. Match over, Wu wins 10-5. So this might seem unfair because Wu had 2 innings,
Shane had 1. But over the course of many matches and many tournaments, they will equal out in who ran the first 5 pack, so they would both have equal innings over the long haul.
Now, lets say Wu, in our hypothetical example, plays Corey. Wu runs 5 racks every inning, Corey runs 2 racks every inning. So in our race to 10, Wu runs 5, Corey runs 2,
Wu runs 5. Game over, Wu wins 10-2. They repeat this over and over. On the sets that Corey goes first, it goes Corey runs 2, Wu runs 5, Corey runs 2, Wu runs 5. Game over, Wu wins 10-4. That's still ok, because the better player gets more "games" every time he steps to the table, because he is a higher skill level. The only way for Corey to get the same amount of "games" is to run more racks every time its his inning. If he does not, then he is clearly not as good as Wu, and thus his rating is appropriately lower.
So, I don't think winner break vs alternate break really makes any difference. All that matters is who wins each game.
Bringing this back to the chess Elo for further discussion, if 2 players play a match, do both have equal opportunities as white? Also, lets say two players only play one single game, then go home. One player will obviously have the advantage being white. Does that game count in the chess Elo ratings?