Is it Possible to CUT AN OBJECT BALL MORE THAN 90°?

dr_dave

Instructional Author
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FYI, I just posted a new video that discusses and demonstrates whether or not it is possible to cut an object ball 90° or more. Be sure to watch to the end. You might find the answers surprising. Check it out:


Contents:
0:00 - Intro
0:46 - Rail Cut Shots
1:57 - Jump Shots
2:55 - Bank Shots
4:13 - Level-Cue Cut Shot
6:54 - With Chalk
8:52 - More Info

Supporting Resources:
As always, I look forward to your feedback, comments, questions, complaints, and requests.

Enjoy!
 
FYI, I just posted a new video that discusses and demonstrates whether or not it is possible to cut an object ball 90° or more. Be sure to watch to the end. You might find the answers surprising. Check it out:


Contents:
0:00 - Intro
0:46 - Rail Cut Shots
1:57 - Jump Shots
2:55 - Bank Shots
4:13 - Level-Cue Cut Shot
6:54 - With Chalk
8:52 - More Info

Supporting Resources:
As always, I look forward to your feedback, comments, questions, complaints, and requests.

Enjoy!
I would say no. Although it can be a accomplished.
 
Depends on what you call cutting the ball.

If i do the shot above and throw the ball to the left side of the pocket in theory i cut above 90 degrees
 
I can't get my head around why it's outside spin. So if I'm cutting 90 degrees to left middle pocket I should use right hand English. Surely hitting cue ball on the right handside will cause it to spin counter clockwise, then gearing effect will cause the object ball to spin clockwise which I'd imagine would make it try and swerve past the middle pocket rather than help.

I presume Dr Dave is correct and I have something wrong in my mental model of the physics. But would appreciate someone telling me where I've gone wrong.
 
... I presume Dr Dave is correct and I have something wrong in my mental model of the physics. But would appreciate someone telling me where I've gone wrong.
If you shoot straight at an object ball with left side spin, does the object ball go to the left or right of the "idea" path, which is straight ahead along the line of centers?
 

Mr. Jewett did this almost 20 years ago. I have referred a lot of people to this video. :love:

Thanks for posting this. I almost included it, but it didn't really add much with the poor video quality and non-ideal camera angle to see the exact angle of the cut. It looks like it was close to 90°, but difficult to tell from the video. Regardless, I have a link to Bob's shots and many other similar impressive shots (several from Joe Tucker) on the "impossible cuts" page linked in the video description.
 
I can't get my head around why it's outside spin. So if I'm cutting 90 degrees to left middle pocket I should use right hand English. Surely hitting cue ball on the right handside will cause it to spin counter clockwise, then gearing effect will cause the object ball to spin clockwise which I'd imagine would make it try and swerve past the middle pocket rather than help.

I presume Dr Dave is correct and I have something wrong in my mental model of the physics. But would appreciate someone telling me where I've gone wrong.

See the illustration and video demonstrations on the Spin-Induced Throw (SIT) resource page. That will help improve your "mental model of the physics." The OB gets thrown during contact. It doesn't not turn/swerve on the way to the pocket (see the OB turn and swerve resource page).
 
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