Have been completed. And they all finished 6-2. The commentators just said it was 15 million to 1 odds as a parlay.
If we assume that the players are of equal ability, we will get the smallest chance that the score will be that lop-sided, but let's go with that to start.
In a single match between two equal players, the chance that Player A will win 6-2 is
2^(-8) * 7*6 /(1*2). Explanation:
The 2 to-the-power-minus-8 is because we have 8 things happening that each has a chance of 1/2
7*6 is from the fact that the two wins by the loser can appear in 7 locations for the first and 6 locations for the second. Neither loss can be the 8th game. Example: WWLWLWWW -- how many different possible strings of W and L are there for 6-2? The answer is 21
The divide by 1, divide by 2 is because the two losses by the winner are indistinguishable.
That gives a chance of Player A winning 6-2 of 21/2^8 or 21/256 or 0.08203125 or a little over 8%
But Player B has the same chance, so the chance that one of them will win at 6-2 is twice or 21/128 =
0.1640625
For that to happen 8 times in a row is that raised to the 8th power or in
1 in 1905133.
