Old Nine Baller
Banned
I understand there can be regional differences in how games are played so I'm trying to understand what you write. You say the 6 would be your "called spot ball" if the 4,6,7,8 & 9 were left. Going by that a person could make the 4/6 combo and win the game, no?
When you are getting the last 4 you don't know what the game-winning balls are until there are 4 balls left on the table is my point.
I also don't understand your distinction between "called spot balls" and "moneyballs". A moneyball is any ball that gives a shooter a win is it not?
Getting the last 4 and making 6 balls on the break and NOT winning is an awfully tough way to play. I've never heard of that before. I would ask this though; if there are only 3 balls left on the table after the break how did the breaker not win or is this an agreed upon method of playing where you are?
ONB
Does anybody make 6 balls on the break with any consistency? I feel like this not being part of the rules before play is more a function of the fact that it is beyond rare for it to happen. If someone does make 6 on the break consistently they should be the one giving weight.
Actually the more meaningful questions in my post were the other ones that were ignored.
I'll answer your question though. If you are giving a person the last 4 and he makes 6 balls on the break then he made one of the last 4. He should win. If it's not played that way in some regions of the country or some drunks in bars play that way then that's up to them.
It doesn't matter if it's "beyond rare" for it to happen. If it happens it should be a win for the breaker and it is in every poolroom I've ever been in. The last 4 is the last 4, it doesn't change because the player receiving the weight is breaking.
To each his own, gambling rules are different everywhere, but would you want to be getting the last 4 and make 6 balls on the break and be told you don't win?
P.S. It happens on bartables more often than anywhere else.
ONB