I can see why you'd imagine that, but imagination isn't as good as actual comparisons of different shafts. It's also easy to imagine that stiffer shafts produce more CB squirt, but that isn't true either (as shown by many tests).
Are you saying that a Predator Z shaft, for example, does not produce less squirt than a Dufferin house cue? That doesn't even sound close to right. There is no question whatsoever that different shafts produce different amounts of cue ball squirt. (as shown by many tests)
Actually, the shaft is set in motion while in contact with the CB, but it does most of its deflecting after separating from the CB, as shown in high speed videos.
That makes sense.
I think this is probably correct. The CB begins to rotate while the tip is in contact with the CB (for 1/1000 of a second or so), so the amount of tip offset from centerball changes during this short time. The amount of spin probably isn't the amount that you'd get if the tip was only in contact with the CB for an instant at one offset distance - the amount of spin probably increases during the entire contact time, and the final amount of spin is probably something like the amount you'd get with an instantaneous contact at somewhere near the point where the CB finally leaves the tip.
While 1/1000 of a second seems like a short period of time in our daily lives, in the lives of forces and vectors, that is an eternity. I think the tip offset changes because the ball is rotating, and the shaft is flexing. If you were to express the forces involved in vectors--look at it this way: any force you apply to the cue ball off center has a component which is acting tangent to the surface of the ball. This is the only component that is important in determining the rotational velocity of the cue ball. No matter where you hit the cue ball and at what angle (at a fixed speed) this force will vary. So I am contending that as the shaft flexes and the ball rotates (which may happen together or not), the forces tangent to the surface of the cueball are changing. Since different shafts flex differently (based at very least on different end masses, different composition, etc.) then there will be a change in the resultant force tangent to the cueball. That differenec might be small, in fact, probably is extremely small. However, factor your 1/1000 of a second time period into the equation, and you now have what amounts to a potentially large difference. Food for thought.
The second half of this statement doesn't follow from the first half unless you can show that different shafts have significantly different contact times. This hasn't been shown, and tests don't show significantly different spin results.
The tests might show otherwise, but the logic is sound. If there is more resultant force for even an instant tangent to the cueballs surface, then there is no need for any increase in contact time. (w=F/t....although actually I believe power (w/t) is a better value to determine the overall spin produced in a unit of time)) Just remember, the force is NOT constant.
Interesting topic!
KMRUNOUT