On an exactly 30 deg. angle shot into a 4 1/2" pocket, how many deg can you be off and still make the ball at pocket speed? Johnnyt
On an exactly 30 deg. angle shot into a 4 1/2" pocket, how many deg can you be off and still make the ball at pocket speed? Johnnyt
I would like to add re: the math involved. Measuring angles here is so not the way to go. You're frequently not aiming for 'center pocket', many tables allow you the cheat the pocket beyond its dimensions using the rubber, etc etc.
It seems that you're trying to standardize things by measuring, but every shot is so different when looked at this way, the results are virtually meaningless.
-s
This question exemplifies what I've been preaching on and off in various threads. This degree thing, IMHO is a very bad way to visualize shots. Not only would I be willing to bet the ranch that you couldn't draw a 30 degree angle on paper time after time without a protractor, but to decide you see one on a pool table and use it as a shooting reference is much more abstract. Besides that, the distance from the OB to the pocket plays way too much into the accuracy of the shot regardless of how well you see degree angles.
Johnny you must have seen the thread on aiming with the side of your cue stick. IMO forgetting TOTALLY about "degree" angles, and practicing this method will raise your game a ton ( provided you have a good level, smooth delivery and complete your stroke properly).
You will need the method less and less and become comfortable knowing the angle of the shot, regardless of specific degrees. In situations where the shot just doesn't feel right, you can always go back to sighting the shot with the side of the cue stick since you are aiming at a definite point with a definite straight edge.
Let's say the OB is a foot away from the jaws, straight out from the pocket (45º), With 4.5" pockets and 2.25" balls, this leaves 1.125" on either side of the ball. So, you've got a right triangle with legs 12" and 1.125". Tangent(theta) = 1.125/12 = 3/32 = 0.09375
so, if tan theta is 0.09375, theta = arctan(0.09375) which comes out to 5.35582505º (0.0934767812rad)
Now 5.35 degrees on a ball 2.25" in diameter means you have a contact point that is 0.21" wide for this shot. {5.35/360 *2.25*2*pi = 0.21009}
On an exactly 30 deg. angle shot into a 4 1/2" pocket, how many deg can you be off and still make the ball at pocket speed? Johnnyt
Thank you for the input. I can pocket balls well so I think I was just trying to find the magic bullet for the whole game after 60 years of playing. I can still beat the 9-ball ghost w/o bih on a bb and
Johnnyt
On an exactly 30 deg. angle shot into a 4 1/2" pocket, how many deg can you be off and still make the ball at pocket speed? Johnnyt
On an exactly 30 deg. angle shot into a 4 1/2" pocket, how many deg can you be off and still make the ball at pocket speed? Johnnyt
Johnny,
For a guy that has been playing this game for 60 years, "can still beat the 9-ball ghost w/o bih on a bb" and supposedly has robbed people at Pool, why do you bother with this trivial stuff that can't help your game? Do you really think your eye can discern between 30 deg and 32 degrees??
I still wonder about some of the weird-azz, novice-like questions you ask, lol!
Eric
Why don't you do both us a favor then and ignore my posts. I mean there only trival anyway and I'm "supposedly" a liar anyway. John Terrell